It's impossible to have an area in cubic units.
Find the area of an equilateral triangle that has a perimeter of 21 inches. Round the answer to one decimal place.
187.10
the answer is 32
use pythagorean theorem. it helps to draw a picture. draw an invisible line from one vertex straight to the opposite side. the hypotenuse is 9, and the shorter leg is half of 9, or 4.5. 81= 20.25 + h squared. height equals 7.7942 and then u round it to 7.8 (x
6.5- you round it until it has one decimal.
Find the area of an equilateral triangle that has a perimeter of 21 inches. Round the answer to one decimal place.
187.10
For an equilateral triangle with side length a, area = (a²√3)/4, which for a= 6cm is 15.6 cm² [rounded to 1 decimal place]
187.10
the answer is 32
Area of equilateral triangle: 0.5*7*7*sin(60 degrees) = 21.2 square inches
To find the area of an equilateral triangle, you can use the formula: area = (sqrt(3)/4) * s^2 where s is the length of one side of the triangle. If the length of one side of the triangle is 6 cm, the area of the triangle is: area = (sqrt(3)/4) * 6^2 = (sqrt(3)/4) * 36 = (3.46/4) * 36 = 13.83 * 36 = 498.68 Rounded to one decimal place, the area of the triangle is approximately 499 cm^2.
Area of equilateral triangle: 0.5*12*12*sin(60 degrees) = 187 square cm
use pythagorean theorem. it helps to draw a picture. draw an invisible line from one vertex straight to the opposite side. the hypotenuse is 9, and the shorter leg is half of 9, or 4.5. 81= 20.25 + h squared. height equals 7.7942 and then u round it to 7.8 (x
7.2
12
idont know people i really search ervery single information but theres nothing its a hexagon,square,circleor an equilateral triangle