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true
The statement is bi-conditional. The "if and only if" should have tipped you off immediately.
False. The question consists of two parts: - a number is divisible by 6 if it is divisible by 3? False. It must also be divisible by 2. - a number is divisible by 6 only if it is divisible by 3? This is true but the false part makes the whole statement false.
No, because the reverse statement may not result in a true statement.(A) If x is an integer then x*x is rational.(B) if x*x is rational then x is an integer.(B) is utter nonsense. x can be any rational number of even a square root of a rational number, for example, sqrt(2/3), and x*x will be rational.
Choose one odd and one even
How can the following definition be written correctly as a biconditional statement? An odd integer is an integer that is not divisible by two. (A+ answer) An integer is odd if and only if it is not divisible by two
true
If a number is nonzero, then the number is positive.
An integer n is odd if and only if n^2 is odd.
If a number is not divisible by two then it is not an even number.
If a number is not even, then it is not divisible by 2.
The statement is bi-conditional. The "if and only if" should have tipped you off immediately.
the number eight
False. The question consists of two parts: - a number is divisible by 6 if it is divisible by 3? False. It must also be divisible by 2. - a number is divisible by 6 only if it is divisible by 3? This is true but the false part makes the whole statement false.
They're ALL divisible by 1... and themselves !
int aNumber = 10; int anotherNumber = 3; if( (aNumber % anotherNumber) == 0 ) { System.out.println("aNumber divisible by anotherNumber"); }else { System.out.println("aNumber NOT divisible by anotherNumber"); }
No, because the reverse statement may not result in a true statement.(A) If x is an integer then x*x is rational.(B) if x*x is rational then x is an integer.(B) is utter nonsense. x can be any rational number of even a square root of a rational number, for example, sqrt(2/3), and x*x will be rational.