If this is a T-F question, the answer is false. It is true that if a number is divisible by 6, it also divisible by 3. This is true because 6 is divisible by 3. However, the converse -- If a number is divisible by 3, it is divisible by 6, is false. A counterexample is 15. 15 is divisible by 3, but not by 6. It becomes clearer if you split the question into its two parts. A number is divisible by 6 if it is divisible by 3? False. It must also be divisible by 2. A number is divisible by 6 only if it is divisible by 3? True.
True. Since 6 is divisible by 2, any number that is divisible by 6 will automatically be divisible by 2.
How can the following definition be written correctly as a biconditional statement? An odd integer is an integer that is not divisible by two. (A+ answer) An integer is odd if and only if it is not divisible by two
False. An enormous number of them are divisible by three.
False, 40 and 80 are examples of numbers ending in 0 and yet evenly divisible by 8
91 x 1 = 91. 13 x 7 = 91. Prime numbers are only divisible by themselves & 1. False 91 is not a prime number.
the answer is no...............................
True. The result is 7,031.
Look at the statement If 9 is an odd number, then 9 is divisible by 2. The first part is true and second part is false so logically the statement is false. The contrapositive is: If 9 is not divisible by 2, then 9 is not an odd number. The first part is true, the second part is false so the statement is true. Now the converse of the contrapositive If 9 is not an odd number, then 9 is not divisible by two. The first part is false and the second part is true so it is false. The original statement is if p then q,the contrapositive is if not q then not p and the converse of that is if not p then not q