end with 5
No. If any number is divisible by 5 and 6, it must also be divisible by 30, which means that it must end with a zero.
There is not always a zero at the end if the number. there is a zero if the number is divisible by five.
To be divisible by 15, it must also be divisible by 3 and by 5. To be divisible by 3, the sum of the digits must be divisible by 3; to be divisible by 5, the number must end with a zero or a five. Considering all these criteria, I guess that number would be 1110.
No, 117 is not divisible by 10 because for a number to be divisible by 10, it must end in 0. In this case, 117 does not end in 0, so it is not divisible by 10.
Five or zero.
Nope ! For ANY number to be exactly divisible by ten it HAS to end in zero !
Nope - it's only divisible by 2. In order to be divisible by 5, it must end in either a 5 or zero. To be divisible by 10 it must end in a zero. For it to be divisible by 3, the total of the digits added together must divide by 3. The same rule applies for it to be divided by 9.
No, 440 is not divisible by 5. In order for a number to be divisible by 5, the last digit must be either 0 or 5. In the case of 440, the last digit is 0, which means it is divisible by 5.
NO. A number divisible by 5 must end in 5 or 0.
no. Here is a rule to learn- If a number is divisible by 5, it must end in 0 or 5. If it does not, it is not divisible by 5. Numbers that end in 1,2,3,4,6,7,8,9 are NOT divisible by 5. (Conversely,) if the number does end in 0 or 5 , it is divisible by 6.
Yes, it is divisible by 10 because it is a number greater than 10 that ends in zero (0), in which case one zero (0) is eliminated from the end of the number and what remains is the quotient.
No. Numbers that are divisible by 2 must end in an even number (0,2,4,6,8)