the midpoint of
Between A and B on the straight line AB.
ac + cb = ab = 9 2x - 1 + 3x = 9 5x -1 = 9 So 5x = 10 Thereby x =2. Also ac = 3 and cb = 6
Cb, Db, Eb, Fb, Gb, Ab, Bb, Cb
Starting with three different letters, six two-letter combinations can be made, if the order of the two letters is important. Only three combinations can be made if the order of the two letters is not important. Example: ABC AB AC BA BC CA CB - six variations But if (for your purposes) BA is the same as AB, Then there are only three: AB AC BC
Gb, Ab, Bb, Cb, Db, Eb, F, Gb
Gb, Ab, Bb, Cb, Db, Eb, F, Gb
the midpoint of AB.
C is not on the line AB.
C is the midpoint of Ab . then AC = BC. So AC= CB.
between A and B
The real answer is Bc . Hate these @
C is not on the line AB.
the midpoint (apex) Between A and B (Apex)
ac + cb = ab = 9 2x - 1 + 3x = 9 5x -1 = 9 So 5x = 10 Thereby x =2. Also ac = 3 and cb = 6
AB + C —> AC + B
.Ab + c cb + a
Ad < dbad < cbad + dc = cbDC + CB = DBAD < CB
AB=2 so A=B/2 AC=CB/2. I guess that wasn't what you were looking for though. But that all that can be done with the information.