the midpoint of
AB plus BC equals AC is an example of the Segment Addition Postulate in geometry. This postulate states that if point B lies on line segment AC, then the sum of the lengths of segments AB and BC is equal to the length of segment AC. It illustrates the relationship between points and segments on a line.
The locus point is the perpendicular bisector of AB. The locus point is the perpendicular bisector of AB.
The Law of Cosines: c^2=a^2 + b^2 -2abcos(ab) , c is the distance between the two points a and b and (ab) is the angle between a and b from the origin. If one point is taken as the origin, and a and b a re taken at right angles to each other, then cos(ab) is zero and you have Pythagora' Theorem..
No, rays AB and BA are not the same ray. A ray is defined by its starting point and extends infinitely in one direction. Ray AB starts at point A and extends through point B, while ray BA starts at point B and extends through point A. Therefore, they originate from different points and have opposite directions.
The real answer is Bc . Hate these @
If AC plus CB equals AB and AC is equal to CB, then point C is the midpoint of segment AB. This means that point C divides the segment AB into two equal parts, making AC equal to CB. Therefore, point C is located exactly halfway between points A and B.
the midpoint of
If point b is in between points a and c, then ab +bc= ac by the segment addition postulate...dont know if that was what you were looking for... but that is how i percieved that qustion.
between A and B
The locus point is the perpendicular bisector of AB. The locus point is the perpendicular bisector of AB.
The point B lies between points A and C is the distances AB, BC and AC are related by:AB + BC = AC.
C is not on the line AB.
Probably an arc, but it is not possible to be certain because there is no information on where or what point b and c are..
The Law of Cosines: c^2=a^2 + b^2 -2abcos(ab) , c is the distance between the two points a and b and (ab) is the angle between a and b from the origin. If one point is taken as the origin, and a and b a re taken at right angles to each other, then cos(ab) is zero and you have Pythagora' Theorem..
the midpoint of AB.
Zero.For instance, given a right triangle with points ABC. where AC is the hypotenuse, then to find the angle between AB, we take sin(AB/AC), where AB is the distance between points A and B, and AC is the distance between A and C. If we replace AB with 0, the equation would be sin(0/AC). Sine of zero is always zero.