A haxagon has 6 sides. An equilateral hexagon has 6 equal sides.
So the perimeter is 6*(2x+1) = 12x+6
Equilateral triangles have three 60' angles, and the angles of any triangle always add to 180'. Attaching squares to each side of an equilateral triangle would also form three obtuse angles (360' - 90'- 90' - 60' = 120') and the resultant obtuse Isosceles triangles' hypotenuses would be greater in length than any side of the square since its two equal sides are the same length as the square. However, the angles of any corner of the newly formed hexagon would be 90' from the square plus 30' (30' = (180' - 120')/2) from the obtuse triangle, making this hexagon equiangular, but not equilateral. JCS
The length of each side is: (12x+21)/3 = 4x+7
6 sides to a hexagon plus 5. The answer you are looking for is 11.
Bruh were are these coming from plus that is true there are six and most of these are concerning.
24
Equilateral triangles have three 60' angles, and the angles of any triangle always add to 180'. Attaching squares to each side of an equilateral triangle would also form three obtuse angles (360' - 90'- 90' - 60' = 120') and the resultant obtuse Isosceles triangles' hypotenuses would be greater in length than any side of the square since its two equal sides are the same length as the square. However, the angles of any corner of the newly formed hexagon would be 90' from the square plus 30' (30' = (180' - 120')/2) from the obtuse triangle, making this hexagon equiangular, but not equilateral. JCS
Since the "slices" of an equilateral hexagon are equilateral triangles, the Pythagorean theorem will solve this problem: A squared plus B squared equals C squared, where A and B are the sides at right angle to each other and C is the hypoteneuse (long side). Slice a 10 inch tall equilateral triangle down the middle. The height A is 10 inches; the base B (1/2 of A) is 5 inches. 10 squared equals 100; 5 squared equals 25. Therefore, the length of each side of the equilateral triangle is the square root of 125, or approximately 11.18 inches. This is also the length of the sides of the hexagon in question.
The length of each side is: (12x+21)/3 = 4x+7
6 sides to a hexagon plus 5. The answer you are looking for is 11.
A regular hexagon and 3 classes of convex hexagons, plus concave hexagons will tessellate.
Bruh were are these coming from plus that is true there are six and most of these are concerning.
In an equilateral triangle, all 3 sides are the same length, so your equation would look something like this: P=the perimeter of the triangle (x+3)=length of each side P=3(x+3) If you wanted to simplify further, you would distribute the 3 to both the x and the 3 inside of the parentheses, giving you P=3x+9.
24
it equals LxL+WxW
No a hexagon has six sides and if u add 2 squares it would have 8 sides witch would turn into a octagon and a triangle plus triangle plus triangleould be a nonagon not a hexagonand if u add it all together it would just be a polygon
8
Perimeter of a triangle = (length of the first side) plus (length of the second side) plus (length of the third side)