Want this question answered?
Mean, median, and mode are all equal in a normal distribution.
No.
The Mean is the average of a given set of values. The Median is the value that has the same number of smaller values than the number of higher values, it is in the middle of them. In a symmetrical distribution the Mean is equal to the Median. In an asymmetrical distribution they have different value.
If there is any skewness in the distribution.
Yes.
If it is a symmetric distribution, the median must be 130.
i) Since Mean<Median the distribution is negatively skewed ii) Since Mean>Median the distribution is positively skewed iii) Median>Mode the distribution is positively skewed iv) Median<Mode the distribution is negatively skewed
That would provide some evidence that the distribution is symmetric about the mean (or median).
for symmetrical distributions your mean equals the median. that is one of the properties of the symmetrical distribution.
That would provide some evidence that the distribution is symmetric about the mean (or median).
If the distribution is not symmetric, the mean will be different from the median. A negatively skewed distribution will have a mean hat is smaller than the median, provided it is unimodal.
The normal distribution.
No. The mean and median are not necessarily the same. They will be the same if the distribution is symmetric but the converse is not necessarily true. That is to say, a distribution does not have to be symmetric for the mean and median to be the same. For example, the mean and median of {1, 1, 5, 6, 12} are both 5 but the distribution is NOT symmetric.
When the distribution has outliers. They will skew the mean but will not affect the median.
Mean
Mean = average and median = the middle value in an array of all values received. So to answer your question the 50th percentile of a distribution is the same as median.
Mean, median, and mode are all equal in a normal distribution.