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Is the velocity of an object changes from 65 ms to 98 ms during a time interval of 12 s what is the acceleration of the object?
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∙ 8y ago
2.75 m/s
Ubaldo Larson
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What are three components needed to find an object acceleration?
Using the definition of acceleration as change of speed / time, you basically need to know: * A time interval during which the object accelerates. * The velocity at the beginning of this time interval. * The velocity at the end of this time interval.
If the speed of an object changes from 121 meters per second to 98 meters per second during a time interval of 12 seconds what is the acceleration of the object?
Acceleration = change in velocity/time a = (v - u) /t where a= acceleration, v= velocity, u= initial velocity & t= time. u = 121 m/s v = 98 m/s t = 12 m/s a = (98 - 121) /12 a = -23/12 a = -1.91667 m/s2
If the speed of an object changes from 121ms to 98 ms during a time interval of 12s what is the acceleration of the object?
Acceleration is equal to the change in velocity over the change in time [a=(vf-vi)/(tf-ti). a=(98m/s - 121 m/s)/(12s)=(-23m/s)/(12s)=-1.92m/s^2
If the speed of an object changes from 121 ms to 98 ms during a time interval of 12s what is the acceleration of the object?
Average acceleration during the time interval = (change on speed) / (time for the change) =(98 - 121) / (12) = -23/12 = negative (1 and 11/12) meters per second2
If the speed of an object changes from 121 ms to 98 ms during a time interval of 12 s what is the acceleration of the object?
-1.92 m/s2
The velocity of a body was noted to be constant during five minutes of its motion What was its acceleration during this interval?
Acceleration means speeding up or slowing down, a change in velocity. Since the velocity was constant, the acceleration was. 0
If the velocity of an object changes from 65 ms to 98 ms during a time interval of 12 s what is the acceleration of the object?
2.75 m/s
What are three components needed to find an object acceleration?
Using the definition of acceleration as change of speed / time, you basically need to know: * A time interval during which the object accelerates. * The velocity at the beginning of this time interval. * The velocity at the end of this time interval.
Does velocity equal acceleration x time?
Yes, sort of. At least, that's the units used. The actual definition of acceleration is: a = dv/dt In other words, the rate at which velocity changes. In the case of constant acceleration, that would be equal to a change in velocity, divided by the time interval during which this change takes place. In the case of non-constant acceleration, the acceleration, or rate of change of velocity, can of course change from one moment to another.
An increase of speed during a given interval of time is called?
The shift of velocity per unit of given time is called acceleration. The types of acceleration are negative acceleration and positive acceleration.
Which physical quantity changes continually during a uniform circular path?
The position, the velocity, and the acceleration.
If the speed of an object changes from 121ms to 98ms during a time interval of 12 s what is the acceleration of the object?
We have this equation: Velocity after = Initial velocity + (acceleration * time) So, let's plug in the numbers into this equation. 98m/s = 121m/s + (acceleration * 12seconds) So, -23 = 12 seconds * acceleration dividing 12 from both sides, the acc. is -1.92m/s/s. (Yes, those are the UNITs of acceleration. And it's negative because the object slows down. )
A skydiver steps from a helicopter and falls for 5 seconds before reaching her terminal velocity during this 5 second interval her acceleration?
the crate will reach terminal velocity last, but hit the ground frist.
If the speed of an object changes from 121 meters per second to 98 meters per second during a time interval of 12 seconds what is the acceleration of the object?
Acceleration = change in velocity/time a = (v - u) /t where a= acceleration, v= velocity, u= initial velocity & t= time. u = 121 m/s v = 98 m/s t = 12 m/s a = (98 - 121) /12 a = -23/12 a = -1.91667 m/s2
A skydiver steps from a helicopter and falls for 5 seconds before reaching her terminal velocity During this 5 second interval her acceleration will?
increase- your speed will increase until terminal velocity is reached. From there it will stay constant.
If the speed of an object changes from 121ms to 98 ms during a time interval of 12s what is the acceleration of the object?
Acceleration is equal to the change in velocity over the change in time [a=(vf-vi)/(tf-ti). a=(98m/s - 121 m/s)/(12s)=(-23m/s)/(12s)=-1.92m/s^2
How is acceleration calcuated?
Dividing change of velocity by the time it takes to change the velocity. If acceleration is not constant, this will give you the average acceleration during the period; to get the instantaneous acceleration, you have to take the derivative of the velocity.
