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If the pole is on level ground then you have the outline of a right angled triangle with an opposite side of 3 feet and an adjacent angle of 30 degrees. To find the length of the adjacent side (which in effect is the shadow of the pole) use the tangent ratio: tangent = opposite/adjacent which can be rearranged to: adjacent = opposite/tangent adjacent = 3/tangent 30o = 5.196152423 feet Therefore the shadow cast by the pole is 5.2 feet corrected to one decimal place.

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Q: If the sun is hitting a pole at 30 degrees altitude and the pole is 3' tall how long is the shadow?
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