It is nearly 40 feet
When the angle of elevation equals 45 degrees. tan-1(1) = 45 degrees.
It is: 27.35 degrees rounded to two decimal places
Angle of elevation = 300/50 = 6 tan-1(6) = 80.53767779 degrees or 800 32' 15.64''
That depends on the angle of elevation which has not been given.
It is: tan(52)*9 = 11.519 meters rounded to three decimal places
The flagpole is 15.92 metres, approx.
36 degrees
If you also know its shadow then you can work out the angle of elevation
If we assume the the flagpole makes a 90 degree angle with the ground, then the angle of elevator for the sun is 34.778°
Use the tangent ratio: tan = 22.5/34 = 45/68 tan-1(45/68) = 33.49518467 degrees Angle of elevation = 33o29'42.66''
21metres
The angle of elevation of the sun can be determined using the tangent function in trigonometry. Specifically, if the height of the flagpole is ( M ) and the length of the shadow is ( m ), the angle of elevation ( \theta ) can be calculated using the formula ( \tan(\theta) = \frac{M}{m} ). To find the angle, use ( \theta = \arctan\left(\frac{M}{m}\right) ). This angle represents how high the sun is in the sky relative to the horizontal ground.
When the angle of elevation equals 45 degrees. tan-1(1) = 45 degrees.
You can use trigonometry to find the angle of elevation. Let x be the distance from the tip of the shadow to the base of the pole and the height of the pole be y. Then, tan(60 degrees) = y/x. Given that the height of the pole is 12 feet, you can solve for x to find the angle of elevation.
It is: 27.35 degrees rounded to two decimal places
Use the tangent angle of elevation which works out as 31.7497 degrees to four decimal places
Using trigonometry the angle of elevation is 77 degrees rounded to the nearest degree