0
If:
xy = x2 + y2 + 2xy
Then:
x2 + xy + y2 = 0
Do you want to solve it for x?
x2 + xy + (y/2)2 = (y/2)2 - y2
(x + y/2)2 = y2/4 - y2
x + y/2 = ± √(-3y2/4)
x = -y/2 ± y√(-3) / 2
x = (-y ± yi√3) / 2
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When x-y equals 7 and xy equals 8 find the value of x square plus y square?
x2 + y2 = x2 - 2xy + y2 + 2xy = (x - y)2 + 2xy = 72 + 2*8 = 49 + 16 = 65 You could, instead, solve the two equations for x and y and substitute, but the above method is simpler.
How do you express x4 plus y4 if given x plus y equals a xy equals b?
(x + y)2 = x2 + 2xy + y2 So x2 + y2 = (x + y)2 - 2xy = a2 - 2b Then (x2 + y2)2 = x4 + 2x2y2 + y4 So x4 + y4 = (x2 + y2)2 - 2x2y2 = (a2 - 2b)2 - 2b2 = a4 - 4a2b + 4b2 - 2b2 = a4 - 4a2b + 2b2
How do you solve 2xy plus 6 equals 4xyz for y?
2xy + 6 = 4xyz Divide through by 2: xy + 3 = 2xyz 3 = 2xyz - xy = y*(2xz - x) Therefore, y = 3/(2xz - x) provided that 2xz - x is not zero.
How do you find the area of a square with a side length of x plus y?
Area of a square = side length squared (x+y)2 (x+y)(x+y) x2+xy+yx+y2 Area = x2+2xy+y2
How do you factorise x3 plus xy-x2y2?
x3+xy-x2y2=x(x2+y-xy2)
What is xy plus xy?
xy + xy = 2xy
When x-y equals 7 and xy equals 8 find the value of x square plus y square?
x2 + y2 = x2 - 2xy + y2 + 2xy = (x - y)2 + 2xy = 72 + 2*8 = 49 + 16 = 65 You could, instead, solve the two equations for x and y and substitute, but the above method is simpler.
How do you express x4 plus y4 if given x plus y equals a xy equals b?
(x + y)2 = x2 + 2xy + y2 So x2 + y2 = (x + y)2 - 2xy = a2 - 2b Then (x2 + y2)2 = x4 + 2x2y2 + y4 So x4 + y4 = (x2 + y2)2 - 2x2y2 = (a2 - 2b)2 - 2b2 = a4 - 4a2b + 4b2 - 2b2 = a4 - 4a2b + 2b2
What is the answer to this math question 3xy-xy-2y plus 5y?
That equals 2xy + 3y which factors to y(2x + 3)
What is the answer of 2xy plus y-3xy?
-1
Xy plus yx equals 545 what is the value of x and y?
xy and yx are identical so you have 2xy = 545 ie xy = 272.5. Possible answers 5 and 54.5, 10.9 and 25 etc
How do you solve 2xy plus 6 equals 4xyz for y?
2xy + 6 = 4xyz Divide through by 2: xy + 3 = 2xyz 3 = 2xyz - xy = y*(2xz - x) Therefore, y = 3/(2xz - x) provided that 2xz - x is not zero.
When will the expression the sum of the squares of two numbers'' and the square of the sum of two numbers'' have the same value?
x2 + y2 = (x + y)2 => x2 + y2 = x2 + 2xy + y2 => 2xy = 0 => xy = 0 So, one of x and y must be 0.
Factor 2xy - 4x plus 8y - 16?
( 2xy - 4x ) + ( 8y - 16)2 ( xy - 2x ) + 2 ( 4y - 8 ) Answer
How do you find the area of a square with a side length of x plus y?
Area of a square = side length squared (x+y)2 (x+y)(x+y) x2+xy+yx+y2 Area = x2+2xy+y2
How do you solve 4x-y2 and 3x y5?
4x-y2=2xy 2x ? y5 if its plus its 7 xy
-3x2-2xY Y2 -4x2-xy 6Y2 x2 xY-Y2?
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