x3+xy-x2y2=x(x2+y-xy2)
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x3 + 2x2 - 8x + 5 = 0 x(2x - 8) + 5 = 0
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(a + 6)(a + 4)
To factorise x3 + 5x2 - 16x - 80 I note that -80 = 5 x -16 and 5 & -16 are the coefficients of x2 and x. Thus I have: x3 + 5x2 - 16x - 80 = (x + 5)(x2 - 16) and the second term is a difference of 2 squares, meaning I have: x3 + 5x2 - 16x - 80 = (x + 5)(x + 4)(x - 4)
p2+10d+7