To shift the absolute value parent function ( F(x) = |x| ) eight units to the left, you replace ( x ) with ( x + 8 ), resulting in ( F(x) = |x + 8| ). Then, to shift the function down three units, you subtract 3 from the entire function, yielding the final equation ( F(x) = |x + 8| - 3 ).
apex what is the range of the absolute... answer is nonnegative real num...
No, the y-intercept is not the same as the absolute value parent function. The absolute value parent function, represented as ( f(x) = |x| ), has a vertex at the origin (0, 0), which serves as its y-intercept. While the absolute value function does have a specific y-intercept, the term "y-intercept" generally refers to the point where any function crosses the y-axis, which can vary depending on the function in question.
To determine the equation of the new function after applying changes to the linear parent function ( f(x) = x ), we need to know the specific transformations applied, such as shifts, stretches, or reflections. For example, if we apply a vertical shift up by 3 units, the new function would be ( f(x) = x + 3 ). If we apply a horizontal shift to the right by 2 units, it would be ( f(x) = x - 2 ). Please provide the specific changes for a precise new equation.
y = b^x
the range is all real numbers
f(x) = |f(x)|/3
It is f(x) = 3|x|.
x2
apex what is the range of the absolute... answer is nonnegative real num...
No, the y-intercept is not the same as the absolute value parent function. The absolute value parent function, represented as ( f(x) = |x| ), has a vertex at the origin (0, 0), which serves as its y-intercept. While the absolute value function does have a specific y-intercept, the term "y-intercept" generally refers to the point where any function crosses the y-axis, which can vary depending on the function in question.
Y=x
To determine the equation of the new function after applying changes to the linear parent function ( f(x) = x ), we need to know the specific transformations applied, such as shifts, stretches, or reflections. For example, if we apply a vertical shift up by 3 units, the new function would be ( f(x) = x + 3 ). If we apply a horizontal shift to the right by 2 units, it would be ( f(x) = x - 2 ). Please provide the specific changes for a precise new equation.
y = b^x
the range is all real numbers
apex what is the range of the absolute... answer is nonnegative real num...
It’s vertex is not at the origin
Yes. (I would like to note that I am not incredibly familiar with this so if someone with more knowledge on the subject wouldn't mind verifying this that would be great.)