Yes. (I would like to note that I am not incredibly familiar with this so if someone with more knowledge on the subject wouldn't mind verifying this that would be great.)
In math a normal absolute value equations share a vertex.
0,0
We will be able to identify the answer if we have the equation. We can only check on the coordinates from the given vertex.
The given equation is not that of a parabola.
7
It’s vertex is not at the origin
Its vertex is not at the origin
Because it farts
vertex
vertex
The graph of a quadratic function is always a parabola. If you put the equation (or function) into vertex form, you can read off the coordinates of the vertex, and you know the shape and orientation (up/down) of the parabola.
There are three main types of vertices for an absolute value function. There are some vertices which are carried over from the function, and taking its absolute value makes no difference. For example, the vertex of the parabola y = 3*x^2 + 15 is not affected by taking absolute values. Then there are some vertices which are reflected in the x-axis because of the absolute value. For example, the vertex of the absolute value of y = 3*x^2 - 15, that is y = |3*x^2 - 15| will be the reflection of the vertex of the original. Finally there are points where the function is "bounced" off the x-axis. These points can be identified by solving for the roots of the original equation. -------------- The above answer considers the absolute value of a parabola. There is a simpler, more common function, y = lxl. In this form, the vertex is (0,0). A more general form is y = lx-hl +k, where y = lxl has been translated h units to the right and k units up. This function has its vertex at (h,k). Finally, for y = albx-hl + k, where the graph has been stretched vertically by a factor of a and compressed horizontally by a factor of b, the vertex will be at (h/b,ak). Of course, you can always find the vertex by graphing, especially since you might not remember the 2nd or 3rd parts above.
The minimum is the vertex which in this case is 0,0 or the origin. There isn't a maximum.....
The graph of the absolute value parent function, ( f(x) = |x| ), has a V-shape with its vertex at the origin (0, 0). It is symmetric about the y-axis, indicating that it is an even function. The graph consists of two linear segments that extend infinitely in the positive y-direction, with a slope of 1 for ( x \geq 0 ) and a slope of -1 for ( x < 0 ). Additionally, it never dips below the x-axis, as absolute values are always non-negative.
x2+8= y This equation represents a function. It will be a parabola with the vertex at (0,8). You can easily graph this on a graphing calculator or from prior knowledge. You know the basic graph of y=x2 with vertex (0,0) and opens upwards on the y-axis. From the equation, you simply shift the vertex vertically up 8 so the new vertex is (0,8) This represents a function because for every x value there is one y value.
In math a normal absolute value equations share a vertex.
To determine the vertex and transformations of a given function, we first need the specific function itself. For example, if the function is in the form (f(x) = a(x-h)^2 + k), the vertex is ((h, k)). The transformations from the parent function (f(x) = x^2) would include a vertical stretch/compression by factor (a), a horizontal shift (h) units, and a vertical shift (k) units. If you provide the specific function, I can give a more detailed answer.