I am assuming that you are not replacing the cards in the deck after each draw.
The probability of drawing no clubs = (52-13)/52*(51-13)/51*(50-13)/50*(49-13)/49
p= 39/52*38/51*37/50*36/49 ~= 0.3038 = 30.38%
The probability of drawing at least one club = 1-0.3038=.6962 = 69.62%
(13*12*11*10)/(52*51*50*49) which works out at11 in 4165
or
about 0.26%
13/204
1 in 52
If only one card is dealt randomly from a deck of cards, the probability is 1/52.
1/13
6/49
It is approx 4.62*10-7.
If dealt from a randomly shuffled pack it is 0.0399, approx.If dealt from a randomly shuffled pack it is 0.0399, approx.If dealt from a randomly shuffled pack it is 0.0399, approx.If dealt from a randomly shuffled pack it is 0.0399, approx.
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There are 52 cards of which 26 (a half) are black. So he probability that the first card is black is 26/52= 1/2
There are 13 clubs in a standard deck of 52 cards. The probability, then, of drawing club is 13 in 52, or 1 in 4, or 0.25.
The probability of drawing two diamonds from a deck of cards is (13 in 52) times (12 in 51), or 156 in 2,652, or 78 in 1,327.
Probability of 2 of clubs = 1/52 or 0.0192.
If the pack is well shuffled, the probability is 1/52.
The minimum number of cards that must be dealt, from an arbitrarily shuffled deck of 52 cards, to guarantee that three cards are from some same suit is 9.The basis for 9 is that the first four cards could be from four different suits, the next four cards could be from four different suits, and the ninth card is guaranteed to match the suit of two of the previously dealt cards. The minimum number, without the guarantee, is 3, but the probability of that is only 0.052, or about 1 in 20.