Probability of 2 of clubs = 1/52 or 0.0192.
If only one card is dealt randomly from a deck of cards, the probability is 1/52.
Since there are only four aces in a standard 52 card deck, the probability of being dealt five aces is zero.
It is 28/52 = 7/13
It is 0.00111 approx.
You have four chances out of 52, therefore 4/52=1/13.
If only one card is dealt randomly from a deck of cards, the probability is 1/52.
The probability is 0. One card cannot be a club and a spade!
If the pack is well shuffled, the probability is 1/52.
The answer will depend on the exact situation.If you are dealt a single card, the probability of that single card not being a queen is 12/13 - assuming you have no knowledge about the other cards.Here is another example. If you already hold three queens in your hand (and no other cards have been dealt), the probability of the next card being dealt being a queen is 1/49, so the probability of NOT getting a queen is 48/49 - higher than in the previous example.
Since there are only four aces in a standard 52 card deck, the probability of being dealt five aces is zero.
If you are drawing two cards from a full deck of cards (without jokers) then the probability will depend upon whether the the first card is replaced before the second is drawn, but the probability will also be different to being dealt a hand whilst playing Bridge (or Whist), which will again be different to being dealt a hand at Canasta. Without the SPECIFIC context of the two cards being got, I cannot give you a more specific answer.
The probability, if the cards are dealt often enough, is 1.On a single deal, the prob is 3.69379*10^-6
Probability = Chance of Success / Total Chances (Chance of Success + Chance of Failure) There are 4 aces in a 52 card deck and 48 cards that are not aces. Probability of being dealt an ace = 4 / (4 + 48) = 4/52 = .0769 or about 7.7 percent
It is 28/52 = 7/13
1/26 under the assumption that one is using a standard 52 card deck with no jokers. 1/27 if the jokers are included.
It is 0.00111 approx.
You have four chances out of 52, therefore 4/52=1/13.