Suppose the 5 letters are A, B, C, D and E.
The letter A can either be in the combination or not: 2 options for A.
With each of these options, B can either be in the combination or not: 2 options for B - making 2*2 options so far.
With each of the options so far, C can either be in the combination or not: 2 options for C - making 2*2*2 options so far.
and so on.
So for 5 letters there are 25 = 32 combinations. However, one of these is the combination that excludes each of the 5 letters - ie the null combination. Excluding the null combination gives the final answer of 31 combinations.
120 ABCDE , there are 120 ways these five letters can be rearranged.
5C3 = 10
one hundred and twenty
3 x 5 = 15
Q: How many letters of alphabet can you make using 5 squares?
7,893,600 (seven million, 8 hundred ninety-three thousand, 600) combinations in English.
120 ABCDE , there are 120 ways these five letters can be rearranged.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
20
The first digit can be one of five integers (1 to 5) The second - fourth digits one of six integers (0 to 5). So: number of (valid) combinations is 5*6*6*6=1080 * * * * * This gives the number of permutations, not combinations. I am working on the latter.
5C3 = 10
To find the number of four-letter words that can be created from the letters in "olvge," we first note that there are 5 unique letters. We can choose 4 letters from these 5 in ( \binom{5}{4} = 5 ) ways. Each selection of 4 letters can be arranged in ( 4! = 24 ) different ways. Therefore, the total number of four-letter combinations is ( 5 \times 24 = 120 ).
one hundred and twenty
Only one.
20 different combinations of silverware
5
3 x 5 = 15