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โˆ™ 2014-06-07 14:52:19
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Algebra

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A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

The sum or difference of p and q is the of the x-term in the trinomial

A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

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Q: How many five number combinations can you make from 5 numbers?
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How many combinations can you make with the numbers 2 3 6 7 and 8?

You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.


How many combinations can you make with three numbers?

You can make 6 combinations with 3 numbers. They are: 123 213 312 132 231 321 * * * * * NO! Those are permutations! In combitorials, the order does not matter so that the combination 123 is the same as the combination 132 etc. So all of the above comprise just 1 combination. With three numbers you can have 1 combination of three numbers (as discussed above), 3 combinations of 2 numbers (12, 13 and 23) 3 combinations of 1 number (1, 2 and 3) In all, with n numbers you can have 2n - 1 combinations. Or, if you allow the null combination (that consisting of no numbers) you have 2n combinations.


How many combinations can you make out of 3 letters and 3 numbers?

You could make 10*10*10*26*26*26 combinations, or 17576000 combinations.


What 3 numbers make 130?

As a product of its prime factors: 2*5*13 = 130


How many 5 numbers combinations can you make from the numbers 1 to 49 and you can use multiple combinations but still use each number only once?

If the 1, 2, 3, 4 and 5 each appear in the numbers (no repeats, no eliminations-- so numbers like 11133 are not valid) then there are 120 combinations. If you can use any of the 5 any number of times up to a max of 5 times, (any possible way of making a 5 digit number using only 1, 2, 3, 4 and 5, so that 33455 for example is valid) then the number of combinations is 3125. The 3125 combinations include the 120 combinations above. This is a permutation of 5 objects, that can be thought of as an arrangement or a rearrangement of the five numbers. The number of permutations of this 5 numbers is equal to 5!. 5! = 5 x 4 x 3 x 2 x 1 = 120 ways. Or you can use the graphing calculator to compute 5!, such as: Press 5, MATH, with the right arrow go to PRB, press 4 (for !), ENTER.

Related questions

How many combinations can you make with the numbers 2 3 6 7 and 8?

You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.


How many numbers can you make with 3 7 8 9?

14 * * * * * Wrong! There are 15. 4 combinations of 1 number, 6 combinations of 2 number, 4 combinations of 3 numbers, and 1 combination of 4 numbers.


How many 2 number combinations can you make with six numbers?

Assuming that the six numbers are different, the answer is 15.


How many 4 number combinations can you make with the numbers zero through nine?

9000


How many 5 numbers combinations can you make from numbers 1 through 35 and you can use multiple combinations but still use each number only once?

35


How many combinations can you make from the numbers 1 2 3 4 5 not multiplying?

The rearrangement of 5 figure numbers will be 5x4x3x2x1 which is 120 combinations, when you don't repeat a number.


How many 4 number combinations can be made out of 3 numbers?

None. You do not have enough numbers to make even one combination.


If you wanted to know how many 5 digit combinations you could make using only 2 digits how would you solve this?

Simple enough to solve. The answer is a power of two. Assuming you have two possible digits, say for example, 3 and 4, then you simply have to multiply it by how many numbers you want to get the total number of combinations. Each number can be 3 or 4 in this case, and you have 5 numbers. That's two to the fifth. Five combinations of any two numbers. 2x2x2x2x2. The answer is 32 combinations.


How many 3 number combinations can you make using the numbers 1-45?

Using the combination fuction, chose three numbers from 45 numbers. The answer is 14,190.


How many combinations of three digits can be made from the numbers 998?

Assuming you are treating each number as a number and not as an individual unit, the numbers you can make from these digits are 899, 989 and 998.


How many combinations can you make with three numbers?

You can make 6 combinations with 3 numbers. They are: 123 213 312 132 231 321 * * * * * NO! Those are permutations! In combitorials, the order does not matter so that the combination 123 is the same as the combination 132 etc. So all of the above comprise just 1 combination. With three numbers you can have 1 combination of three numbers (as discussed above), 3 combinations of 2 numbers (12, 13 and 23) 3 combinations of 1 number (1, 2 and 3) In all, with n numbers you can have 2n - 1 combinations. Or, if you allow the null combination (that consisting of no numbers) you have 2n combinations.


How is four on the middle of five?

well 5 is an odd number there for 2 numbers can't be added to make odd numbers so 4 is the closest number to five so we use it as the middle number for five :D

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