You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
To calculate the number of combinations with three numbers, you would use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n is the total number of numbers you have to choose from, and r is the number of numbers you are choosing. So, if you have three numbers to choose from, there would be 3C3 = 3! / 3!(3-3)! = 6 / (6*0!) = 6 / 6 = 1 combination.
No there actually more combinations that we can make with numbers than letters. That's not actually true, since there are more letters than numerals, but every combination of numerals is a number and there are an infinite number of them, whereas, not all combinations of letters actually make words--there is only a finite number of words.
You could make 10*10*10*26*26*26 combinations, or 17576000 combinations.
As a product of its prime factors: 2*5*13 = 130
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
14 * * * * * Wrong! There are 15. 4 combinations of 1 number, 6 combinations of 2 number, 4 combinations of 3 numbers, and 1 combination of 4 numbers.
Assuming that the six numbers are different, the answer is 15.
35
9000
Simple enough to solve. The answer is a power of two. Assuming you have two possible digits, say for example, 3 and 4, then you simply have to multiply it by how many numbers you want to get the total number of combinations. Each number can be 3 or 4 in this case, and you have 5 numbers. That's two to the fifth. Five combinations of any two numbers. 2x2x2x2x2. The answer is 32 combinations.
The rearrangement of 5 figure numbers will be 5x4x3x2x1 which is 120 combinations, when you don't repeat a number.
None. You do not have enough numbers to make even one combination.
Using the combination fuction, chose three numbers from 45 numbers. The answer is 14,190.
Assuming you are treating each number as a number and not as an individual unit, the numbers you can make from these digits are 899, 989 and 998.
First you need to find you first number. As there are five numbers, the first number can be any of the five. So you have five combinations (5). Next you take your second number, as you've already used one you can only choose one of four numbers (5 x 4). You third number, you can only choose one of three numbers (5 x 4 x 3), you fourth, one of two (5 x 4 x 3 x 2) and finally you are left with one number, so you only have one choice. So we have a combination of 5 x 4 x 3 x 2 x 1 (or 5!) to find the number of different 5 number combinations you can make with 1, 2, 3, 4 and 5. Answer: 120.
The five that immediately come to mind (and I assume you are looking for) are: 12345 23451 34512 45123 51234 However, these are not the only combinations available as demonstrated below. Note: This just a representative sampling and is not all inclusive. 21345 23145 23415 13245 13425 13452