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There are 21 possible results. Of the 21, there are 3 ways it can end up to have the sum of 7 (1 and 6, 2 and 5, 3 and 4). 3/21*100%=14.3% (14.3% chance to get 7)

If there repetition is allowed (like 4 for dice A and 5 for dice B + 5 for dice A and 4 for dice B is 2 counts), there will be 36 possible results. There will also be 6 possible ways to get two numbers to have a sum of 7. 6/36=16.7% (16.7% chance to get 7)

There is also another situation where the meaning of the question is to roll a 7 from another dice (example n-sided dice). Chances of getting a 7 from two dices is 2/n (if n is less than 7 excluding 7, it is unsolvable)

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15y ago

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