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You need to take the magnitude of the cross-product of two position vectors. For example, if you had points A, B, C, and D, you could take the cross product of AB and BC, and then take the magnitude of the resultant vector.
The term given to the net figure that results from vector addition is the resultant vector. It represents the combined effect of two or more individual vectors in terms of both magnitude and direction.
If the vectors are added tip to tail and form a closed figure, the resultant will be zero. This is because the vectors cancel each other out in such a way that the initial point and final point coincide, resulting in no displacement overall.
That's it! You know everything there is to know about it. It's not as if you have to wander through a crowd of vectors and find one that matches the description. "Find the vector" means figure out its magnitude and direction. If the problem already gave you the magnitude and direction, then it's unlikely that it's asking you to 'find' that same vector.
yes the resultant of the two vectors can be zero.it can be illustrated by drawing following diagram.a triangle may be considered as a vector diagram in which the force polygon close and the resultant of the three vectors is zero.
A triangle...
a = (change in speed) divided by (time for the change)
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The net figure that results from vector addition is called the resultant. It represents the combined effect of all the individual vectors.
figure it out
Consider two vectors A and B Represented by directionel lines OM and ON respectivelynow add the two vectors by head to tail tail of vector addition now resolve it into rectangular components as shown in figure
Gravity is a vector, because it is a form of acceleration (which we know by definition is a vector). Vectors hold more 'information' than scalars, because vectors are, put simply, a scalar + a direction. To help you figure out these types of questions in the future, all you have to do is figure out whether direction is an important aspect of the value in question.