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In a gm ABCD the bisector of angle A also bisect BC at X. Prove tht AD2 AB?
Wiki User
∙ 7y ago
AX bisects angle DAB so angles DAX and XAB are equal. .. .. .. .. .. .. .. .. (i)
DA is parallel to CB and AX is an intercept.So angle DAX and AXB are alternate angles and therefore angles DAX and AXB are equal.
Therefore, by (i) angles XAB and AXB are equal.
Thus triangle BAX is isosceles
therefore AB = BX.
BX = 1/2*BC = 1/2*AD (since ABCD is a parallelogram).
Therefore AB = BX = AD/2.
Wiki User
∙ 7y ago
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A quadrilateral is a parallelogram if a pair of opposite sides is equal and parallel prove?
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"abcd is not a parallelogram or it does not have any right angles." ~(P and Q) = ~P or ~Q
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Abcd is a quadrilateral angle a equals 40 degrees and angle b equals 150 degrees could abcd be a trapezoid?
never
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never
A quadrilateral is a parallelogram if a pair of opposite sides is equal and parallel prove?
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Dihedral angle
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none of these answers are correct
What is the negation of the statement quadrilateral abcd is a paralleogram and it has a right angle?
"abcd is not a parallelogram or it does not have any right angles." ~(P and Q) = ~P or ~Q
ABCD is a quadrilateral in which angle A 40 degrees and angle B 150 degrees. Could ABCD be a parallelogram?
for a+ NEVERIn a parallelogram opposite angles are equal. Thus angle c = angle a = 40o.The sum of all the angles in a quadrilateral is 360o, so:angle a + angle b + angle c + angle d = 360o=> 40o + angle b + 40o + angle d = 360o=> angle b + angle d = 280o.
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none of these are correct
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