Q: If ABCD is a parallelogram what can we say about the diagonals BD and AC?

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The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals: Area = (1/2) * ( 12 * 7) = 42.

If abcd is a parallelogram, then the lengths ab and ad are sufficient. The perimeter is 36 units.

58.5

The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals:Area = (1/2) * ( 12 * 7) = 42.The way this works: for a rhombus, the diagonals bisect each other (they intersect at the other's midpoint), so split this into two identical triangles BCD and BAD.The area of one of these triangles is (1/2) * Base * Height, with Base = length of BD, and Height = 1/2 length of AC.So area of one triangle = (1/2) * BD * ((1/2)*AC), and area of rhombus is 2 * area of triangle, so you have 2 * (1/2) * BD * ((1/2)*AC) = (1/2) * (BD) * (AC)

A = (1/2)(ac)(bd) = (1/2)(8)(9) = 36

Related questions

The diagonals arenotthe sides. They're lines you draw from one angle of the parallelogram to the angle opposite it. So if you have parallelogram ABCD, your diagonals are AC and BD, because AB, BC, CD, and DA are all sides.

In parallelogram ABCD, AC=BD. Is ABCD a rectangle?

Yes, it is.

never

Only if parallelogram is in the form of a rectangle will AC equal BD because a square is not a parallelogram.

What id actually says is... What fits in the blank? Diagonal AC of Parallelogram ABCD _____ bisects angle A and angle C.

The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals: Area = (1/2) * ( 12 * 7) = 42.

If abcd is a parallelogram, then the lengths ab and ad are sufficient. The perimeter is 36 units.

this is what you would: 4x+6=3x-1 -6 -6 ---- 4x=3x-7 -3x -3x ---- 1x=-7 ---- x=-7

A quadrilateral is a parallelogram if one pair of opposite sides are equal and parallel Let ABCD be a quadrilateral in which ABCD and AB=CD, where means parallel to. Construct line AC and create triangles ABC and ADC. Now, in triangles ABC and ADC, AB=CD (given) AC = AC (common side) Angle BAC=Angle ACD (corresponding parts of corresponding triangles or CPCTC) Triangle ABC is congruent to triangle CDA by Side Angle Side Angle BCA =Angle DAC by CPCTC And since these are alternate angles, ADBC. Thus in the quadrilateral ABCD, ABCD and ADBC. We conclude ABCD is a parallelogram. var content_characters_counter = '1032';

A rhombus has two lines of symmetry. They are also called its diagonals. Suppose there is a rhombus ABCD AC and BD are its lines of symmetry.

No. If two lines intersect they cross each other. To bisect each other, means that the lines not only intersect but that also that the point where the two line[ segment]s cross is the mid point of both of the line[ segment]s. Examples, consider: The diagonals of a kite ABCD with sides AB & AD equal (2 cm each), and BC & DC equal and twice the length of the other two sides (4 cm each). The diagonals AC and BD intersect each other; BD is bisected by AC but AC is NOT bisected by BD. The diagonals of a right angle trapezium ABCD with ∠DAB and ∠ADC right angles (so sides AB and DC are parallel) and with sides AB = 2 cm, CD = 14 cm and AD = 5 cm (side BC = 13 cm). The diagonals AC and BD intersect, but NEITHER bisects the other. The diagonals AC and BD of a square ABCD not only intersect each other, but they also do, in this case, bisect each other.