Yes, because that is how remainder is defined. If the remainder was bigger, you would subtract one (or more) modular values until the remainder became smaller than the modulus.
Physiologic density is always greater than arithmetic density. It is based on the amount of arable land (which is always likely less than the total area), which makes the density greater because it uses a smaller area.
The remainder must always be smaller.
It SHOULD always be less than the divisor... Otherwise your answer is wrong.
Because if the remainder is greater, then you could "fit" another divisor value into it. if they are equal, then you can divide it easily. Thus, the remainder is always lower than the divisor.
A clock is modular math. It has a base twelve. We use a base ten. If the clock had ten hours in a half day then the remainder when dividing would always be our answer.
The geometric mean, if it exists, is always less than or equal to the arithmetic mean. The two are equal only if all the numbers are the same.
Because if the remainder is greater, then you could "fit" another divisor value into it. if they are equal, then you can divide it easily. Thus, the remainder is always lower than the divisor.
Any pair of numbers will always form an arithmetic sequence.
Not always as for example 12/3 = 4 and no remainder but 13/3 = 4 with a remainder of 1
It must be less else you have not divided properly; you could divide again 1 or more times!If the remainder is equal to the divisor (or equal to a multiple of the divisor) then you could divide again exactly without remainder. If the remainder is greater but not a multiple of the divisor you could divide again resulting in another remainder.E.g. Consider 9/2. This is 4 remainder 1. Let's say our answer was 3 remainder 3; as our remainder "3" is greater than the divisor "2" we can divide again so we have not carried out our original division correctly!
The sequence is arithmetic if the difference between every two consecutive terms is always the same.
The remainder is always 31 or less.