12
-1
2x - 5y = -10 So 5y = 2x + 10 and therefore y = (2/5)*x plus something So the slope is 2/5 or 0.4
8
(4,2), (2,1),(-2,-1)
10
With great difficulty because without an equality sign the given expression can't be considered to be a straight line equation
If you mean: y = 2x +6 then the slope of the line is 2
It is 2√5 ≈ 4.47 units.To solve this:Find the equation of the line perpendicular to y = 2x + 10 that passes through the point (2, 4);Find the point where this line meets y = 2x + 10Find the distance from this point to (2, 4) using PythagorasThe slope of the perpendicular line (m') to a line with slope m is such that mm' = -1, ie m' = -1/mFor y = 2x + 10, the perpendicular line has slope -1/2, and so the line that passes through (2, 4) with this slope is given by:y - 4 = -½(x - 2)→ 2y - 8 = -x + 2→ 2y + x = 10To find where this meets the line y = 2x + 10, substitute for y in the equation of the perpendicular line and solve for x:y = 2x + 102y + x = 10→ 2(2x + 10) + x = 10→ 4x + 20 + x = 10→ 5x = -10→ x = -2Now use one of the equations to solve for y:y = 2x + 10→ y = 2(-2) + 10→ y = -4 + 10 = 6This the perpendicular line from (2, 4) meets the line y = 2x + 10 at the point (-2, 6)The distance between these two points is given by:distance = √((-2 - 2)² + (6 - 4)²) = √(16 + 4) = √20 = 2√5 ≈ 4.47 units
Without an equality sign the given terms can't be considered to be a straight line equation.
2x+y = 10 or y = -2x + 10 so the slope is -2
Put in this form. Y = mX + c 2X - 5Y = 10 - 5Y = - 2X + 10 Y = (2/5)X - 2 ================
The answer depends on the sign preceding the value 15 (which is not given in the question). If y = -2x+15 then (0,15) if y= -2x-15 then (0,-15)
y - 2x is not an equation. If that is supposed to be y = 2x then the slope is 2. Or, written as a slope, would be 2/1
12
2x = 3y + 10 is linear. !!!! In straight line form it is 3y = 2x - 10 y = (2/3)x - 10/3
If you mean: y = -2x-5 then the slope is -2 and the y intercept is -5