The points are: x = 0 and y = -1/10.
4x - 10y = 11Add 10y to each side:4x = 11 + 10ySubtract 11 from each side:4x - 11 = 10yDivide each side by 10:y = f(x) = 0.4x - 1.1
x = 6y = 89x + 10y = 9(6) + 10(8) = 54 + 80 = 134
what is the solution of x-5y=10 and 2x-10y=20
y=(x+2)/(x+10) xy+10y=x+2 xy-x=2-10y x(y-1)=2-10y x=(2-10y)/(y-1)
y - intercept = 10x - intercept = -10y- intercept: x = 0y = x + 10y = 0 + 10y = 10x - intercept: y = 0y = x + 100 = x + 10x + 10 = 0x = -10
Y=-1/2(x)
4x-10y=11 4x=11+10y 10y+11=4x 10y=4x-11 y=(4/10)x-(11/10) y=(2/5)x-(11/10)
y + x = 9 10y + 20x = 100 This is a basic linear system of equalities. We can start by rewriting the first equation as: -10y - 10x = -90 by multiplying the equation by -10, from here we can eliminate y and solve for x (-10y - 10x = -90) + (10y + 20x = 100) = (10x = 10) This yields x = 1, and by plugging x into the first equation y = 8
10 is.
18 + 70 ie 87
If you mean: -10x-10y = -20 then x intercept is at (2, 0) and y intercept at (0, 2)