Best Answer

yes

for a number to be divisble by 3

you have to add the numbers together and see if you can divide it by 3 evenly

1+5+3= 9

9 can be divided by 3 evenly so that makes the number, 153 divisble by 3

Q: Is 153 divisible by 3

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The sum of the digits of a multiple of 3 sum to a number that is itself divisible by 3. Example : 153 : 1 + 5 + 3 = 9 which is divisible by 3 so 153 is a multiple of 3. But : 206 : 2 + 0 + 6 = 8 shows that 206 is NOT a multiple of 3.

Yes, 153 is divisible by 9 because all the digits add up to 9 (i.e 1+5+3 = 9) As a rule of thumb, add the digits of a number together. If the sum is a multiple of 9, it is divisible by nine.

D

Yes, 51 times.

Nope ! For ANY number to be exactly divisible by ten it HAS to end in zero !

Related questions

No, 153 is only divisible by: 1, 3, 9, 17, 51, 153.

All are divisible by 3 if you don't mind that the answer is not a whole number. However, if you are looking for the number which is evenly divisible by 3 (resulting in a whole number) then it is 153. 153/3 = 51.

No, 49 cannot be divided by 3 evenly. 43 divided by 3 is equal to 16⅓. A general way of knowing if a number is divisible by 3 is by finding the sum of the individual numbers that is being divided. If the sum itself is divisible by 3, then the number is likewise also divisible. For example, the problem stated is 49/3. In 49, 4+9=13. Because 13 is not evenly divisible by 3, 49 also cannot be evenly divided by 3. In another example, the problem stated is 153/3. In 153, 1+5+3=9. Because 9 is divisible by 3, 153 is also likewise divisible by 3. 153/3=51.

1,377 is divisible by: 1, 3, 9, 17, 27, 51, 81, 153, 459, 1377.

1,3,9,17,51,153

The sum of the digits of a multiple of 3 sum to a number that is itself divisible by 3. Example : 153 : 1 + 5 + 3 = 9 which is divisible by 3 so 153 is a multiple of 3. But : 206 : 2 + 0 + 6 = 8 shows that 206 is NOT a multiple of 3.

Yes, 153 is divisible by 9 because all the digits add up to 9 (i.e 1+5+3 = 9) As a rule of thumb, add the digits of a number together. If the sum is a multiple of 9, it is divisible by nine.

1, 3, 9, 17, 51, 153, 289, 867, 2601.

D

Nope. 9,333 is divisible by 1, 3, 9, 17, 51, 61, 153, 183, 549, 1037, 3111, 9333.

Seven and 153.

Yes, 51 times.