Yes. 195/3=65. 65x3=195.
Multiples of 195.
if all the digits add up to a number divisible by 3 like 195 195= 1+9+5= 15...15/3=5 so it is divisible by 3
well, 1+9=10+5=15, which is divisible by 3, so it should be according to 3's divisabilaty rule.
No - 195/2 = 97.5
39, 78, 117, 195, 312 and 936 are divisible by three.
Yes and it is 195/5 = 39
All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 195 is a 5 which is NOT a 0, so 195 is NOT divisible by 10.
Add the digits in 585 i.e. 5+8+5=18 18 is divisible by 3 Therefore, 585 is divisible by 3
135. Every increase of 30 is also. Such as 165, 195, 225.
585 is divisible by these numbers: 1 3 5 9 13 15 39 45 65 117 195 and 585.
195.
Any of its multiples