195.
195 is composite because it is divisible by 5.
Multiples of 195.
if all the digits add up to a number divisible by 3 like 195 195= 1+9+5= 15...15/3=5 so it is divisible by 3
No - 195/2 = 97.5
Yes. 195/3=65. 65x3=195.
Yes and it is 195/5 = 39
All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 195 is a 5 which is NOT a 0, so 195 is NOT divisible by 10.
135. Every increase of 30 is also. Such as 165, 195, 225.
Because any number ending with 5 or 0 is divisible by 5 except of course 0 by itself
1, 3, 5, 13, 15, 39, 65, 195.
No, 585 is divisible by 5, 15, 117, 39, 3, 195, 9, and 65.