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Q: Is 1 2 7 3 6 divisible by 4 and 9?

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not divisible by 9.but it is divisible by 4.

the least number divisible by 1, 2, 3, 4 & 6 is 12.

1, 2, 0, 3 and 8 are not divisible by 4 and/or 9. Neither is 12038.

352 is divisible by 1, 2, 4 and 8; not by 3, 5, 6 and 9

no because: 1+4+1+2=8 and 8 is not divisible by 3.

It is divisible only by 3; It is not divisible by 2, 4, 5, 6, 9, 10. 17211 is odd, so not divisible by 2, 4, 6 nor 10. 1 + 7 + 2 + 1 + 1 = 12 which is divisible by 3, so 17211 is divisible by 3, but 12 is not divisible by 9, so 17211 is not divisible by 9. 17211 does not end in 5 or 0 so not divisible by 5

1+4+3 = 8 which is not divisible by 3, so 143 is not divisible by 3. 8 ÷ 3 has remainder 2, so 143 ÷ 3 has remainder 2.

It is divisible by 1, 2 and 4.

1, 2 and 3

1, 2, 3, 4, and 6

are 2 and 8 divisible by 4

A number is divisible by 6 if it is divisible both by 2 and 3 1240 is even then is divisible by 2 1+2+4+0 = 7 which is not divisible by 3 then 1240 is not divisible by 3 Thus 1240 is not divisible by 6

4 is divisible by 1, 2 and 4 because 1 x 4 and 2 x 2 = 4

There is no 4-digit number that is divisible by zero.

The largest 4 digit number that is divisable by 1 2 3 and 4 is........9996

2463. The trick is that a number is divisible by 3 if and only if the sum of its digits is divisible by 3. 1+3+2+4 = 10 (not divisible by 3), while 2+4+6+3 = 15 (divisible by 3).

4 is divisible by 1, 2 and 4.

1+1+3+8+6+5 = 24 2+4=6 6 is divisible by 3 so 113865 is divisible by 3.

A Harshad number is a positive integer which is is divisible by the sum of its digits. There are many Harshad numbers, for example, 1, 2, 3, 4, 5, 6, 7, 8, 9, 18 (1 + 8 = 9 and 18 is divisible by 9), 21 (2 + 1 = 3 and 21 is divisible by 3), and 24 ( 2 + 4 = 6 and 24 is divisible by 6).

4 is divisible by 1, 2 and 4.

4 is divisible by 1, 2 and 4.

To determine if a number is divisible by 6, it must be divisible by both 2 and 3. To determine if a number is divisible by 2, it should be even - in other words, it should end with 0, 2, 4, 6, or 8. To determine if a number is divisible by 3, the sum of its digits should be divisible by 3. 54,132 is an even number, so it is divisible by 2. 5 + 4 + 1 + 3 + 2 = 15, which is divisible by 3, so 54,132 is divisible by 3. Since 54,132 is divisible by both 2 and 3, it is divisible by 6.

No. It is divisible by 5 (it ends in a five) and by 3 (1+2+3+4+5=15 which is divisible by three).

7 + 4 + 1 = 12 which is divisible by 3, so 741 is divisible by 3 741 is odd, all multiples of 4 are even, 741 is not divisible by 4 (Alternatively 4 x 2 + 1 x 1 = 9 which is not divisible by 4, so 741 not divisible by 4) All multiples of 5 end with 5 or 0, 741 ends with 1, so 741 not divisible by 5 To be divisible by 6, the number must be divisible by 2 (even) and divisible by 3.741 is odd, so not divisible by 2, so 741 is not divisible by 6 7 + 4 + 1 = 12 which is not divisible by 9, so 741 is not divisible by 9 All multiples of 10 end with 0, 741 ends with 1 so 741 is not divisible by 10 Summary: 741 is divisible by 3, but not by 4, 5, 6, 9 nor 10.

9996