1, 2, 0, 3 and 8 are not divisible by 4 and/or 9.
Neither is 12038.
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If you multiply 417 by any integer (0, 1, 2, 3, -1, -2, -3, etc.), you will get a number that is divisible by 417.If you multiply 417 by any integer (0, 1, 2, 3, -1, -2, -3, etc.), you will get a number that is divisible by 417.If you multiply 417 by any integer (0, 1, 2, 3, -1, -2, -3, etc.), you will get a number that is divisible by 417.If you multiply 417 by any integer (0, 1, 2, 3, -1, -2, -3, etc.), you will get a number that is divisible by 417.
The sum of its digits is 1+2+0 = 3 which is divisible by 3. So 120 is divisible by 3. The number 120 ends in a 0 and so it is divisible by 5.
yes, 0 is divisible by everything.
2390 is not divisible by 3 but is divisible by 5. 2 + 3 + 9 + 0 = 14; 1 + 4 = 5: 5 is not divisible by 3, so 14 is not divisible by 3, so 2390 is not divisible by 3. 2390 ends with a 0, so 2390 is divisible by 5.
Check your divisibility rules: 2: One's digit is an even number YES 3: The sum of the digits is divisible by 3 NO: 7 + 1 + 0 = 8 which is not divisible by 3 5: One's digit is a 5 or a 0 YES 9: The sum of the digits is divisible by 9 NO: 7 + 1 + 0 = 8 which is not divisible by 9 10: One's digit is a 0 YES