Q: Is 1 plus 1 plus 1 divisible by 3?

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3 is divisible by 1 and 3 because 1 x 3 = 3

3 is divisible by 1 and 3 because 1 x 3 = 3

It is divisible by 3, for example.It is divisible by 3, for example.It is divisible by 3, for example.It is divisible by 3, for example.

3 is divisible by only 1 and 3.

Is it divisible

No it is not divisible by 3. 88/3= 27 1/3

NO. 1110 is not divisible by 9. A number is divisible by 9 if the sum of its digits is divisible by 9. 1110 = 1 + 1 + 1 + 0 = 3 (3 is not divisible by 9, thus, 1110 is not divisible by 9.)

NO. 313 is not divisible by 3.A number is divisible by 3 if the sum of the digits is divisible by 3.313 = 3 + 1 + 3 = 7Note: 7 not divisible by 3 thus, 313 is not divisible by 3.

No. 1+9+6=16, which is not divisible by 3; 1+4+6=11, which isn't divisible by 3 either. No. 1+9+6=16, which is not divisible by 3; 1+4+6=11, which isn't divisible by 3 either.

No. If a number is divisible by three, the sum of its digits will be divisible by three. Obviously, the sum of the digits of 10000 is 1, and 1 is not divisible by 3, so 10000 is not divisible by 3.

1+1+3+8+6+5 = 24 2+4=6 6 is divisible by 3 so 113865 is divisible by 3.

To be divisible by 6, the number must be divisible by both 2 and 3:To be divisible by 2 the last digit must be even, ie one of {0, 2, 4, 6, 8};To be divisible by 3, sum the digits of the number and if this sum is divisible by 3, then the original number is divisible by 3.As the test can be repeated on the sum, repeat the summing until a single digit remains; only if this number is one of {3, 6, 9} is the original number divisible by 3.If the number is not divisible by 2 or 3 (or both) then the number is not divisible by 6.examples:126Last digit is even so it is divisible by 2 1 + 2 + 6 = 9 which is divisible by 3, so it is divisible by 3â†’ 126 is divisible by both 2 and 3, so it is divisible by 6124Last digit is even so it is divisible by 2 1 + 2 + 4 = 7 which is not divisible by 3, so it is not divisible by 3â†’ 126 is divisible by 2 but not divisible by 3, so it is not divisible by 6123Last digit is not even so it is not divisible by 2 We can stop at this point as regardless of whether it is divisible by 3 or not, it will not be divisible by 6. However, for completeness:1 + 2 + 3 = 6 which is divisible by 3, so it is divisible by 3â†’ 123 is divisible by 3 but not divisible by 2, so it is not divisible by 6121Last digit is not even so it is not divisible by 2 We can stop at this point as regardless of whether it is divisible by 3 or not, it will not be divisible by 6. However, for completeness:1 + 2 + 1 = 4 which is not divisible by 3, so it is not divisible by 3â†’ 121 is not divisible by either 2 or 3, so it is not divisible by 6

1 and 3.

If sum of digits of a number is divisible by 3 then the number is divisible by 3. Sum of digits = 5+1+8 = 14 and 14 is not divisible by 3. So 518 is not divisible by 3.

no because: 1+4+1+2=8 and 8 is not divisible by 3.

If sum of digits of a number is divisible by 3 then the number is divisible by 3. Sum of digits = 1+3+4+5+6 = 19 and 19 is not divisible by 3. So 13456 is not divisible by 3.

3+1+3+3+3+4+3+4+1+1+1+1+1+1+5+6 =41 Every operation is addition so all the adding can happen in one step.

yes. 2 + 1 + 6 = 9 9 is divisible by 3 so 216 is divisible by 3.

142 is not divisible by 3. 142 divided by 3 = 47 and 1/3

No, 64 is not divisible by 3. 64 = 3 x 21 + 1

Because 3 is larger than 1. A number can't be divisible by a larger number.

yes and if you ever want to know if something is divisible by 3 add up the number like 3 plus 3 (33) is 6 and it is divisible by 3. by the way the answer is 11. 11x3=33

Let three consecutive integers be n, n+1 and n+2. If n is divisible by 3 then n+1 and n+2 cannot be divisible by 3 as these numbers will respectively leave remainders of 1 and 2. If n is not divisible by 3 then it will leave a remainder of 1 or 2. If n leaves a remainder of 1, then n+1 leaves a remainder of 2 and n+2 is therefore divisible by 3. If n leaves a remainder of 2, then n+1 is divisible by 3 and n+2 is not divisible by 3 as it leaves a remainder of 1.

Yes, it is divisible by 2 because it ends with 2, it is also divisible bye 3 because 1+3+2=6. 6 is divisible by 3, therefor 132 is divisible by 3.

between 1 and 600 inclusive there are:300 numbers divisible by 2200 numbers divisible by 3100 numbers divisible by both 2 and 3400 numbers divisible by 2 or 3.