23/3 = 7 and 2/3 = 7.666 (recurring) in decimal
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Yes and it is 23
This is an easy one, if you know a little trick -> add up the digits ! 2 + 0 + 7 = 9. Is this divisible by 3 ? Yes ! then 207 is divisible by three. Divide it, you get 69. Add the digits = 15, also divisible by 3. Divide again, you get 23. So, 207 is divisible by 3 3 23.
The factors of 69 are 1, 3, 23, and 69.
To determine if a number is divisible by both 2 and 3, we need to check if it is divisible by the least common multiple of 2 and 3, which is 6. 4671 is not divisible by 6 because the sum of its digits (4 + 6 + 7 + 1 = 18) is not divisible by 3, making 4671 not divisible by 3. 3858 is divisible by 6 because the sum of its digits (3 + 8 + 5 + 8 = 24) is divisible by 3, making 3858 divisible by 3 and 2. 6494 is not divisible by 6 because it is an odd number, making it not divisible by 2, and the sum of its digits (6 + 4 + 9 + 4 = 23) is not divisible by 3, making 6494 not divisible by 3.
3= no 4=yes 92 divided by 3 = 30.666666 92 divided by 4= 23