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Q: How do you solve 2ab-3b2-3b plus 2a?

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(2a + 1)(4a2 - 2a + 1)

Subtract 2a from each side: P - 2a = b ie b = P - 2a

a = 4

depends what 'a' =

If: 2a+13 = 5a+1 Then: a = 4

-2a + 5 = 1 -2a = -5 + 1 -2a = -4 a = -4/-2 a = 2

Solve the following equation for A : 2A/3 = 8 + 4A

:a = .5(hb+c) :2a = hb+c :2a−c = hb :(2a−c)/h = b

a + a + a - 2a = 3a - 2a = a

2a+2a-7b+7b =4a

2a + a = 3a

What is the solution of -2a plus 3a plus 5b

a+a=1 2a=1 a=1/2

2a + 2b = c subtract 2a from both sides 2a - 2a + 2b = c - 2a 2b = c - 2a divide both sides by 2 (2/2)b = (c - 2a)/2 b = (c - 2a)/2 --------------------

8b -2a

4a

the answer

2a + 2b = 160 But b = a + 40 so 2a + 2(a + 40) = 160 ie 2a + 2a + 80 = 160 or 4a = 80 ie a = 20 Then b = a + 40 gives b = 20 + 40 = 60 Solution: a = 20, b = 60

2a-3+4b-2a-b-2a-b-3+5 Can be simplified to: 3b-1

x + 2a

A = h/2*(a + b) So 2A/h = a + b and therefore, a = 2A/h - b

2a-3+4b-2a-b-3+5=3b-1

Without an inequality sign it can't be considered to be an equation but it can be simplified to: 4-2a

(2a+1)(a+1)

2a+5a+9a = 16a