No, it is not.
Yes: 261 ÷ 9 = 29
yes but not evenly 261/6=43.5
yes
Every number is divisible by any non-zero number.The prime factorisation is 261 = 3^2*29, so it has 6 factors.
All numbers that end with 0, 2, 4, 6, or 8 are divisible by 2.
it is divisible by 3, 261 x 3 = 783
Yes. An easy way to see if any number can be divided by 3, is to add up the digits in the number. If the digits in the number add up to a multiple of three, it is divisible by 3. 261 --> 2 + 6 + 1 = 9 (9 is divisible by 3, so in turn 261 is also) 210 --> 2 + 1 + 0 = 3 (3 can be divided by itself, so 210 is divisible by 3) 8349 --> 8 + 3 + 4 + 9 = 24 (24/3=8, so 8349 is divisible by 3)
261, 264, or 267
1,827 is divisible by: 1, 3, 7, 9, 21, 29, 63, 87, 203, 261, 609, 1827.
A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.
No. 1,827 is only divisible by 1, 3, 7, 9, 21, 29, 63, 87, 203, 261, 609, 1827.
4 is not divisible by 684. 684 is divisible by 4.