yes
All numbers that end with 0, 2, 4, 6, or 8 are divisible by 2.
No. 1,827 is only divisible by 1, 3, 7, 9, 21, 29, 63, 87, 203, 261, 609, 1827.
If a number is divisible by 2 and 3, it is divisible by 6.
To determine if 483 is divisible by 6, we need to check if 483 divided by 6 results in a whole number. When we divide 483 by 6, we get 80 with a remainder of 3. Since there is a remainder, 483 is not divisible by 6.
Every number is divisible by any non-zero number.The prime factorisation is 261 = 3^2*29, so it has 6 factors.
Yes: 261 ÷ 9 = 29
No, it is not.
261, 264, or 267
yes
All numbers that end with 0, 2, 4, 6, or 8 are divisible by 2.
Yes. An easy way to see if any number can be divided by 3, is to add up the digits in the number. If the digits in the number add up to a multiple of three, it is divisible by 3. 261 --> 2 + 6 + 1 = 9 (9 is divisible by 3, so in turn 261 is also) 210 --> 2 + 1 + 0 = 3 (3 can be divided by itself, so 210 is divisible by 3) 8349 --> 8 + 3 + 4 + 9 = 24 (24/3=8, so 8349 is divisible by 3)
it is divisible by 3, 261 x 3 = 783
1,827 is divisible by: 1, 3, 7, 9, 21, 29, 63, 87, 203, 261, 609, 1827.
6 is not divisible by 162. 162 is divisible by 6.
To determine if 483 is divisible by 6, we need to check if 483 divided by 6 results in a whole number. When we divide 483 by 6, we get 80 with a remainder of 3. Since there is a remainder, 483 is not divisible by 6.
No. 1,827 is only divisible by 1, 3, 7, 9, 21, 29, 63, 87, 203, 261, 609, 1827.