1,827 is divisible by: 1, 3, 7, 9, 21, 29, 63, 87, 203, 261, 609, 1827.
The factors of 261 are: 1, 3, 9, 29, 87, 261
81: 8 + 1 = 9 which is divisible by 9, so 81 is divisible by 9 162: 1 + 6 + 2 = 9 which is divisible by 9, so 162 is divisible by 9 199: 1 + 9 + 9 = 19 → 1 + 9 = 10 → 1 + 0 = 1 which is not divisible by 9, so 199 is not divisible by 9. 1125: 1 + 1 + 2 + 5 = 9 which is divisible by 9, so 1125 is divisible by 9. So 199 is the only one not divisible by 9.
yes, nine. 29 x 9=261.
Yes, 441 is divisible by 9. To determine if a number is divisible by 9, you can add up its digits. In this case, 4 + 4 + 1 = 9, which is divisible by 9. Therefore, 441 is divisible by 9.
Every number is divisible by any non-zero number.The prime factorisation is 261 = 3^2*29, so it has 6 factors.
No, it is not.
1,827 is divisible by: 1, 3, 7, 9, 21, 29, 63, 87, 203, 261, 609, 1827.
yes but not evenly 261/6=43.5
No. 1,827 is only divisible by 1, 3, 7, 9, 21, 29, 63, 87, 203, 261, 609, 1827.
yes
Yes. An easy way to see if any number can be divided by 3, is to add up the digits in the number. If the digits in the number add up to a multiple of three, it is divisible by 3. 261 --> 2 + 6 + 1 = 9 (9 is divisible by 3, so in turn 261 is also) 210 --> 2 + 1 + 0 = 3 (3 can be divided by itself, so 210 is divisible by 3) 8349 --> 8 + 3 + 4 + 9 = 24 (24/3=8, so 8349 is divisible by 3)
1, 3, 9, 23, 29, 69, 87, 207, 261, 667, 2001, 6003
These numbers between 200 and 300 are divisible by nine but not by two: 207, 225, 243, 261, 279, 297.
1, 3, 5, 9, 15, 29, 45, 87, 145, 261, 435, 1305.
9 times 29 = 261
The factors of 261 are 1, 3, 9, 29, 87, and 261. The prime factors of 261 are 3 x 3 x 29.1, 3, 9, 29, 87, 261