NO.
No, 118 is not divisible by 9 without a remainder.
58.2222
9.524 of course is 9 524/1000, but this is not in lowest terms because 524 and 1000 both are divisible by 4. Dividing both by 4 we get 9 131/250. The only prime factors of 250 are 2 and 5, neither of which divides 131, so this is now in lowest terms.
NO. 1110 is not divisible by 9. A number is divisible by 9 if the sum of its digits is divisible by 9. 1110 = 1 + 1 + 1 + 0 = 3 (3 is not divisible by 9, thus, 1110 is not divisible by 9.)
No, not without getting a remainder of 1. In decimal, this is 372.1111111111111111111111111
Yes and No if you want a whole number WITHOUT DECIMALS its impossible. The Answer is 0.00165289
81: 8 + 1 = 9 which is divisible by 9, so 81 is divisible by 9 162: 1 + 6 + 2 = 9 which is divisible by 9, so 162 is divisible by 9 199: 1 + 9 + 9 = 19 → 1 + 9 = 10 → 1 + 0 = 1 which is not divisible by 9, so 199 is not divisible by 9. 1125: 1 + 1 + 2 + 5 = 9 which is divisible by 9, so 1125 is divisible by 9. So 199 is the only one not divisible by 9.
No it is not divisible by 9 .
All numbers divisible by 3 are NOT divisible by 9. As an example, 6, which is divisible by 3, is not divisible by 9. However, all numbers divisible by 9 are also divisible by 3 because 9 is divisible by 3.
"Divisible by" means that you can carry out the division, and that you'll get a whole number. Or, if you use whole number division, that there will be no remainder. For example: 8 divided by 2 = 4, remainder zero. 8 is divisible by 2. On the other hand, 9 divided by 2 = 4, remainder 1 (on a calculator, you get decimals: 4.5). That means that 9 is not divisible by 2.
No - any number divisible by 9 will have the sum of its digits divisible by 9.
30,030,003 is divisible by 9 without a remainder. Both 30,030,003 and 9 are odd numbers. Therefore, an even number such as 8 would always leave a remainder.