No.
No. 527 is divisible by 1, 17, 31, 527.
Every number is divisible by any non-zero number. 527 is not evenly divisible by 3.
3
No
No - 527/7 = 75.285714 recurring (that is, 75.285714285714...)
Its factors are: 1, 17, 31 and 527
NO. 1110 is not divisible by 9. A number is divisible by 9 if the sum of its digits is divisible by 9. 1110 = 1 + 1 + 1 + 0 = 3 (3 is not divisible by 9, thus, 1110 is not divisible by 9.)
81: 8 + 1 = 9 which is divisible by 9, so 81 is divisible by 9 162: 1 + 6 + 2 = 9 which is divisible by 9, so 162 is divisible by 9 199: 1 + 9 + 9 = 19 → 1 + 9 = 10 → 1 + 0 = 1 which is not divisible by 9, so 199 is not divisible by 9. 1125: 1 + 1 + 2 + 5 = 9 which is divisible by 9, so 1125 is divisible by 9. So 199 is the only one not divisible by 9.
No.A very quick way to know whether or not a number is divisible by is adding up the numbers within the number. And see if the new number is divisible by 3.For instance, the number 527, add 5, 2, and 7 together. (5+2+7=14) The answer, 14, is not divisible by 3.Another example would be the number 168. 1+6+8=15 The number 15 is divisible by 3, therefore the number 168 is divisible by 3.
No it is not divisible by 9 .
All numbers divisible by 3 are NOT divisible by 9. As an example, 6, which is divisible by 3, is not divisible by 9. However, all numbers divisible by 9 are also divisible by 3 because 9 is divisible by 3.
No - any number divisible by 9 will have the sum of its digits divisible by 9.