Q: Is 534 divisible by 2 3 5 9 or 10?

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1, 2, 3, 6, 89, 178, 267, 534.

to find out wheathr a certain number is divisible by 3 just add up the digits. for ex:- 534=5+3+4=12=1+2=3 since 3 is divisible by 3 therefore 534 is divisible by 3

Yes, to check for divisibility by three, use the sum of digits method: 5 + 3 + 4 = 12. Twelve is divisible by 3, so 534 is also divisible by 3

No. To test: add the digits together and if the sum is divisible by 9, so is the original number. The test can be repeated on the sum until a single digit remains. If this single digit is 9 then the [original] number is divisible by 9, otherwise it gives the remainder when the [original] number is divided by 9. 534 → 5 + 3 + 4 = 12 12 → 1 + 2 = 3 3 ≠ 0 so 12 is not divisible by 9 so 534 is not divisible by 9; the remainder when 534 is divided by 9 is 3.

It is divisible by 2 and 3. It isn't divisible by 5 and 10.

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It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10

No, but 534 is divisible by 2 and 3.

Out of that list, 534 is divisible by 2 and 3.

2:yes 3:no ? 5:no 9:no ? 10:no

1, 2, 3, 6, 89, 178, 267, 534.

1, 2, 3, 6, 89, 178, 267, 534.

to find out wheathr a certain number is divisible by 3 just add up the digits. for ex:- 534=5+3+4=12=1+2=3 since 3 is divisible by 3 therefore 534 is divisible by 3

Yes, to check for divisibility by three, use the sum of digits method: 5 + 3 + 4 = 12. Twelve is divisible by 3, so 534 is also divisible by 3

No. To test: add the digits together and if the sum is divisible by 9, so is the original number. The test can be repeated on the sum until a single digit remains. If this single digit is 9 then the [original] number is divisible by 9, otherwise it gives the remainder when the [original] number is divided by 9. 534 → 5 + 3 + 4 = 12 12 → 1 + 2 = 3 3 ≠ 0 so 12 is not divisible by 9 so 534 is not divisible by 9; the remainder when 534 is divided by 9 is 3.

It is divisible by 2 and 3. It isn't divisible by 5 and 10.

534 = (5 x 10^2) + (3 x 10^1) + (4 x 10^0)

It is evenly divisible by 2 and 10 but not by 3 and 9.