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It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10

No, but 534 is divisible by 2 and 3.

Out of that list, 534 is divisible by 2 and 3.

2:yes 3:no ? 5:no 9:no ? 10:no

1, 2, 3, 6, 89, 178, 267, 534.

1, 2, 3, 6, 89, 178, 267, 534.

to find out wheathr a certain number is divisible by 3 just add up the digits. for ex:- 534=5+3+4=12=1+2=3 since 3 is divisible by 3 therefore 534 is divisible by 3

Yes, to check for divisibility by three, use the sum of digits method: 5 + 3 + 4 = 12. Twelve is divisible by 3, so 534 is also divisible by 3

No. To test: add the digits together and if the sum is divisible by 9, so is the original number. The test can be repeated on the sum until a single digit remains. If this single digit is 9 then the [original] number is divisible by 9, otherwise it gives the remainder when the [original] number is divided by 9. 534 → 5 + 3 + 4 = 12 12 → 1 + 2 = 3 3 ≠ 0 so 12 is not divisible by 9 so 534 is not divisible by 9; the remainder when 534 is divided by 9 is 3.

It is divisible by 2 and 3. It isn't divisible by 5 and 10.

It is evenly divisible by 2 and 10 but not by 3 and 9.

Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.

9 is divisible by 3 10 is divisible by 2, 5 and 10. Everything else, no.

20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.

534 = (5 x 10^2) + (3 x 10^1) + (4 x 10^0)

It is divisible by 2, 5 and 10, but not 3 and 9.

29,178 is divisible by 2, 3 and 9, not by 5 or 10.

Because 410 ends in 0, it is divisble by 10. To determine if it's divisible by 6, it needs to be divisible by 2 and 3. it is divisible by 2, as it is even, but is not divisible by 3;

It is divisible by 2, 5 and 10 but not the rest.

No since only numbers in which its sum can be divisible by 3 is divisible by 3. 2 + 4 + 4 is 10, and 10 is not divisible by 3.

Last digit (0) is even, so it is divisible by 2 4 + 3 + 2 + 0 = 9 which is divisible by 3, so it is divisible by 3 last digit is 0 or 5, so it is divisible by 5 4 + 3 + 2 + 0 = 9 which is divisible by 9, so it is divisible by 9 last digit is 0, so it is divisible by 10 → 4320 is divisible by all the numbers 2, 3, 5, 9, 10

475 is evenly divisible by 5, but not by 2, 3, 4, or 10.

It is divisible by 3.

Yes it is divisible by 2

It is only divisible by 3, and not 2, 4, 5, 6, or 10.