534 = (5 x 10^2) + (3 x 10^1) + (4 x 10^0)
It is evenly divisible by 2 and 10 but not by 3 and 9.
Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.
20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.
It is divisible by 2, 5 and 10, but not 3 and 9.
It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10
It is evenly divisible by 2 and by 3.
No, but 534 is divisible by 2 and 3.
Out of that list, 534 is divisible by 2 and 3.
1, 2, 3, 6, 89, 178, 267, 534.
1, 2, 3, 6, 89, 178, 267, 534.
to find out wheathr a certain number is divisible by 3 just add up the digits. for ex:- 534=5+3+4=12=1+2=3 since 3 is divisible by 3 therefore 534 is divisible by 3
Yes, to check for divisibility by three, use the sum of digits method: 5 + 3 + 4 = 12. Twelve is divisible by 3, so 534 is also divisible by 3
No. To test: add the digits together and if the sum is divisible by 9, so is the original number. The test can be repeated on the sum until a single digit remains. If this single digit is 9 then the [original] number is divisible by 9, otherwise it gives the remainder when the [original] number is divided by 9. 534 → 5 + 3 + 4 = 12 12 → 1 + 2 = 3 3 ≠ 0 so 12 is not divisible by 9 so 534 is not divisible by 9; the remainder when 534 is divided by 9 is 3.
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
534 = (5 x 10^2) + (3 x 10^1) + (4 x 10^0)
It is evenly divisible by 2 and 10 but not by 3 and 9.