Both 57 and 9 are divisible by 3. So, 19/3 would be 57/9 in it's most reduced form.
No.
57 = 3 x 19 so 57 is divisible by 1, 3, 19 and 57.
No. 57 is divisible by 3.
3, yes. All the rest, no.
Yes, 57/3 = 19
1, 3, 19, 57.
3, 9, 19, 57, 171, 361, 1083.
No. it is composite. 57 is divisible by 3 and 19 :)
57 is divisible by 1, 3, 19 and 57.
1, 3, 19, 57.
You can see quickly that the number 57 is divisible by 3: 3 * 20 = 60 so if we remove one of those 3's then 3 * 19 = 57 so it is divisible by at least 3 and 19 (as well as itself and 1) Because it is divisible by numbers other than itself and one, 57 cannot be prime. You can also check to see if a number is divisible by 3 by adding its digits and checking to see if that number is divisible by 3: 5+7 = 12 ; and 12 is divisible by 3, so 57 is as well.