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# Is 5890 divisible by 2 3 6 9 5 10?

Updated: 9/20/2023

Wiki User

12y ago

Test of divisibility by 2:

If a number is even then the number can be evenly divided by 2.

5890 is an even number so, it is divisible by 2.

Test of divisibility by 3:

A number is divisible by 3 if the sum of digits of the number is a multiple of 3.

Sum of digits = 5+8+9+0 = 22, which is not a multiple of 3.

So, 5890 is not divisible by 3.

Test of divisibility by 6:

In order to check if a number is divisible by 6, we have to check if it is divisible by both 2 and 3 because 6 = 2x3.

As we have seen above that 5890 is not divisible by 3 so, 5890 fails to pass the divisibility test by 6.

Test of divisibility by 9:

If the sum of digits of a number is divisible by 9 then the number is divisible by 9.

Sum of digits = 5+8+9+0 = 22, which is not a multiple of 9.

So, 5890 is not divisible by 9.

Test of divisibility by 5:

If the last digit of a number is 0 or 5, then it is divisible by 5.

It is clear that 5890 is divisible by 5.

Test of divisibility by 10:

If the last digit of a number is 0, then the number is divisible by 10.

It is clear that 5890 is divisible by 10 as the last digit is 0.

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12y ago

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Q: Is 5890 divisible by 2 3 6 9 5 10?
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Related questions

### Is 5890 divisible by3?

5890 &divide; 3 = 1963.33 recurring.

No.

### Is 3 divisible by 5890?

A trick here is to use something called the digital root (take the sum of all the digits until you have a single digit.) 5 + 8 + 9 + 0 = 22; 2 + 2 = 4 Anything divisible by 3 will have a digital root of 3, 6, or 9. Therefore, 5890 is not divisible by 3 [without a remainder.]

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