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Q: Is 5890 divisible by 3 6 9?

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Test of divisibility by 2:If a number is even then the number can be evenly divided by 2.5890 is an even number so, it is divisible by 2.Test of divisibility by 3:A number is divisible by 3 if the sum of digits of the number is a multiple of 3.Sum of digits = 5+8+9+0 = 22, which is not a multiple of 3.So, 5890 is not divisible by 3.Test of divisibility by 6:In order to check if a number is divisible by 6, we have to check if it is divisible by both 2 and 3 because 6 = 2x3.As we have seen above that 5890 is not divisible by 3 so, 5890 fails to pass the divisibility test by 6.Test of divisibility by 9:If the sum of digits of a number is divisible by 9 then the number is divisible by 9.Sum of digits = 5+8+9+0 = 22, which is not a multiple of 9.So, 5890 is not divisible by 9.Test of divisibility by 5:If the last digit of a number is 0 or 5, then it is divisible by 5.It is clear that 5890 is divisible by 5.Test of divisibility by 10:If the last digit of a number is 0, then the number is divisible by 10.It is clear that 5890 is divisible by 10 as the last digit is 0.

The trick to determining whether a number is divisible by 9 is to add all the individual numbers of the large number together and see if the result is divisible by 9. Let's add 5 + 8 + 9 + 0 = 22. Since 22 is not neatly divisible by 9, then we know that the larger 5890 is also not divisible by 9. Of course, you can divide it by 9, but there will be something left over.

72,344 is not evenly divisible by 3 or by 6 or by 9.

42 is divisible by 2, 3 and 6 but not by 9.

All numbers divisible by 9 are divisible by 3; since 9 = 3 x 3 all multiples of 9 are also multiples of 3. However, all numbers divisible by 3 are not divisible by 9, eg 6 = 2 x 3 but 6 is not divisible by 9 (since 6 is not a multiple of 9) - it only takes one counter example to disprove a theory.

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Test of divisibility by 2:If a number is even then the number can be evenly divided by 2.5890 is an even number so, it is divisible by 2.Test of divisibility by 3:A number is divisible by 3 if the sum of digits of the number is a multiple of 3.Sum of digits = 5+8+9+0 = 22, which is not a multiple of 3.So, 5890 is not divisible by 3.Test of divisibility by 6:In order to check if a number is divisible by 6, we have to check if it is divisible by both 2 and 3 because 6 = 2x3.As we have seen above that 5890 is not divisible by 3 so, 5890 fails to pass the divisibility test by 6.Test of divisibility by 9:If the sum of digits of a number is divisible by 9 then the number is divisible by 9.Sum of digits = 5+8+9+0 = 22, which is not a multiple of 9.So, 5890 is not divisible by 9.Test of divisibility by 5:If the last digit of a number is 0 or 5, then it is divisible by 5.It is clear that 5890 is divisible by 5.Test of divisibility by 10:If the last digit of a number is 0, then the number is divisible by 10.It is clear that 5890 is divisible by 10 as the last digit is 0.

yes!

is not

A trick here is to use something called the digital root (take the sum of all the digits until you have a single digit.) 5 + 8 + 9 + 0 = 22; 2 + 2 = 4 Anything divisible by 3 will have a digital root of 3, 6, or 9. Therefore, 5890 is not divisible by 3 [without a remainder.]

No because: 5+8+9+0=22 22 is not divisible by 6.

Multiples of 9 and 6 are also divisible by three, the reverse is not true. 15 is divisible by 3, but not 6 or 9. 27 is divisible by 3 and 9, but not 6. 12 is divisible by 3 and 6, but not 9. 54 is divisible by 3, 6 and 9.

The trick to determining whether a number is divisible by 9 is to add all the individual numbers of the large number together and see if the result is divisible by 9. Let's add 5 + 8 + 9 + 0 = 22. Since 22 is not neatly divisible by 9, then we know that the larger 5890 is also not divisible by 9. Of course, you can divide it by 9, but there will be something left over.

No, 9 is divisible by 3 and 9, but not six 3 x 9 = 27, also not divisible by 6

72,344 is not evenly divisible by 3 or by 6 or by 9.

1350 is divisible by all of the numbers of 3, 6 and 9

42 is divisible by 2, 3 and 6 but not by 9.

All numbers divisible by 9 are divisible by 3; since 9 = 3 x 3 all multiples of 9 are also multiples of 3. However, all numbers divisible by 3 are not divisible by 9, eg 6 = 2 x 3 but 6 is not divisible by 9 (since 6 is not a multiple of 9) - it only takes one counter example to disprove a theory.