yes!
Yes, both.
5,890 is divisible by: 1, 2, 5, 10, 19, 31, 38, 62, 95, 155, 190, 310, 589, 1178, 2945 and 5890.
5,890 is divisible by: 1, 2, 5, 10, 19, 31, 38, 62, 95, 155, 190, 310, 589, 1178, 2945, 5890.
Test of divisibility by 2:If a number is even then the number can be evenly divided by 2.5890 is an even number so, it is divisible by 2.Test of divisibility by 3:A number is divisible by 3 if the sum of digits of the number is a multiple of 3.Sum of digits = 5+8+9+0 = 22, which is not a multiple of 3.So, 5890 is not divisible by 3.Test of divisibility by 6:In order to check if a number is divisible by 6, we have to check if it is divisible by both 2 and 3 because 6 = 2x3.As we have seen above that 5890 is not divisible by 3 so, 5890 fails to pass the divisibility test by 6.Test of divisibility by 9:If the sum of digits of a number is divisible by 9 then the number is divisible by 9.Sum of digits = 5+8+9+0 = 22, which is not a multiple of 9.So, 5890 is not divisible by 9.Test of divisibility by 5:If the last digit of a number is 0 or 5, then it is divisible by 5.It is clear that 5890 is divisible by 5.Test of divisibility by 10:If the last digit of a number is 0, then the number is divisible by 10.It is clear that 5890 is divisible by 10 as the last digit is 0.
Yes; 1178.
A trick here is to use something called the digital root (take the sum of all the digits until you have a single digit.) 5 + 8 + 9 + 0 = 22; 2 + 2 = 4 Anything divisible by 3 will have a digital root of 3, 6, or 9. Therefore, 5890 is not divisible by 3 [without a remainder.]
because 10 is also divisible by 2 and 5.
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
1, 2, 5, 10, 19, 31, 38, 62, 95, 155, 190, 310, 589, 1178, 2945, 5890
Because 10 is divisible by both 2 and 5
10 / 2 = 5 10 / 5 = 2
Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.