Yes, it is. It can be determined in moments, without doing the division, by calculating the core digit of the number, which is 9. Every number with a core digit value of 9 is a multiple of 9, and therefore a multiple of 3.
No 13 is not divisible by 3 because there would be a remainder of 1 and a number that is divisible by another should have no remainder
How about 27
1+4+3 = 8 which is not divisible by 3, so 143 is not divisible by 3. 8 ÷ 3 has remainder 2, so 143 ÷ 3 has remainder 2.
Yes, it is divisible by three, and more than that, there will be no remainder.
To check if a number is divisible by another number, we divide. When we divide, there cannot be a remainder. For example, is 9 divisible by 3? Yes, it is because 9 divided by 3 is 3 without a remainder. How about 4? No, because when we divide 4 by 3 there is a remainder of 1. nycfunction@yahoo.com sum of the numbers in the given digits should be divisible by 3.then we can say that it is divisible by 3.example :22344 is divisible by 3.since2+2+3+4+4=15.so the given digit is divisible by 3
No 13 is not divisible by 3 because there would be a remainder of 1 and a number that is divisible by another should have no remainder
How about 27
1+4+3 = 8 which is not divisible by 3, so 143 is not divisible by 3. 8 ÷ 3 has remainder 2, so 143 ÷ 3 has remainder 2.
Yes but it will have a remainder
No, 83 is not divisible by 3. When a number is divisible by another number, it means that the division will result in a whole number without a remainder. In this case, when you divide 83 by 3, you get 27 with a remainder of 2, which means 83 is not divisible by 3.
Yes, it is divisible by three, and more than that, there will be no remainder.
Let three consecutive integers be n, n+1 and n+2. If n is divisible by 3 then n+1 and n+2 cannot be divisible by 3 as these numbers will respectively leave remainders of 1 and 2. If n is not divisible by 3 then it will leave a remainder of 1 or 2. If n leaves a remainder of 1, then n+1 leaves a remainder of 2 and n+2 is therefore divisible by 3. If n leaves a remainder of 2, then n+1 is divisible by 3 and n+2 is not divisible by 3 as it leaves a remainder of 1.
To check if a number is divisible by another number, we divide. When we divide, there cannot be a remainder. For example, is 9 divisible by 3? Yes, it is because 9 divided by 3 is 3 without a remainder. How about 4? No, because when we divide 4 by 3 there is a remainder of 1. nycfunction@yahoo.com sum of the numbers in the given digits should be divisible by 3.then we can say that it is divisible by 3.example :22344 is divisible by 3.since2+2+3+4+4=15.so the given digit is divisible by 3
939 is evenly divisible by 3 939 is divisible by 8, but not evenly, quotient is 117, remainder is 3
No. Add the digits of the dividend and if that is divisible by 3 then the original number is divisible by 3; if not, its remainder when divided by 3 gives the remainder when the original number is divided by 3: 1 + 2 + 1 = 4 which gives a remainder of 1 when divided by 3, so 121 divided by 3 gives a remainder of 1. (121 = 40 x 3 + 1)
It is not EVENLY divisible by three. You can divide it by three, but you will have a remainder. 95347/3 = 31782.333333333...
Yes, but not without a remainder.