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Is every number that is divisible by 9 divisible by 3?
Yes, every number that's divisible by 9 is divisible by 3
What number is divisible by 10 but not 5?
Every number divisible by 10 is divisible by 5.
What are numbers divisible of 2?
Every even number is divisible by 2.
How many number is divisible by 17?
Every multiple of 17 is divisible by 17. There are an infinite number of them.
What are the divisibility rules for 1-13?
14
Is 234678 divisible by 4?
To determine if a number is divisible by 4, we look at the last two digits of the number. In this case, the last two digits of 234678 are 78. For a number to be divisible by 4, the last two digits must form a number that is divisible by 4. Since 78 is not divisible by 4, 234678 is not divisible by 4.
What is the converse inverse and contrapositive If every digit of a number is divisible by 3 then the number is divisible by 3?
Converse:If a number is divisible by 3, then every number of a digit is divisible by three. Inverse: If every digit of a number is not divisible by 3 then the number is not divisible by 3? Contrapositive:If a number is not divisible by 3, then every number of a digit is not divisible by three.
Is every number that is divisible by 9 divisible by 3?
Yes, every number that's divisible by 9 is divisible by 3
Is 62 divisible by every number?
Every number? No. It isn't divisible by 61, for instance.
Is 78 divisible by 2356and 9?
No. 78 is not divisible by 2356.
Is 78 divisible by 9?
No, 78 is not evenly divisible by 9.
What number is not divisible by 9?
Every number is divisible by 9 but the answer wont necessarily be a whole number.
What number is divisible by 3 2 and 13?
All of the multiples of 78 are. There are an infinite number of them.
Is the number 78 is divisible by 2 and 3?
yes to both.
What number is divisible by 10 but not 5?
Every number divisible by 10 is divisible by 5.
How can you know if 6 is a factor of 78?
For a number to be divisible by 6, it has to be divisible by 2 and 3, because 2*3=6.In other words, we could divide the number we're factorising (78) by the prime factors of the number we're testing (6, which is 2*3). We start by dividing by 2, because we know 78 is even: 78/2=39. Then, we divide the new number by the other prime factor - 3. 39/3=13 13 is a whole number with no remainders, therefore we can say that 78 is divisible by 6, and therefore 6 is a factor of 78. (6*13=78)
If every digit of a number is divisible by 3 then the number itself is divisible by 3?
Yes.
