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Q: If every digit of a number is divisible by 3 then the number itself is divisible by 3?

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Converse:If a number is divisible by 3, then every number of a digit is divisible by three. Inverse: If every digit of a number is not divisible by 3 then the number is not divisible by 3? Contrapositive:If a number is not divisible by 3, then every number of a digit is not divisible by three.

I'm not quite sure about that theory, but if all the numbers in the number add up to a number that's dividable by 3, then the number itself would then be divisible by 3. Ex. 141 1+4+1= 6 6 is divisible by 3, so 141 is too. 141/3= 47.

Every multiple of 593 is divisible by 593: 593, 1186, 1779, 2372, and so on.

Every number is divisible by 9 but the answer wont necessarily be a whole number.

NO, can 2 be divided by 6........ yes, can 4 be divided by 6......... Every number is divisible by every other number, but not always exactly. Not every number that is exactly divisible by 2 is exactly divisble by 4. Examples: 2, 18, 30, 46

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Converse:If a number is divisible by 3, then every number of a digit is divisible by three. Inverse: If every digit of a number is not divisible by 3 then the number is not divisible by 3? Contrapositive:If a number is not divisible by 3, then every number of a digit is not divisible by three.

Every number divisible by 10 is divisible by 5.

every alternate number from 100 to 998

Every sixth number from 1,002 to 9,996 is divisible by 3 and 6. There are 1,500 of them.

Yes. Every non-zero number is divisible by itself.

A prime number is one that has only two factors: one and itself.You can tell if a number is prime quickly by using the Laws of Divisibility:Numbers that end in 0, 2, 4, 6, and 8 are divisible by 2.If the sum of a number's digit is divisible by 3, the number itself is divisible by 3.If the last two digits of a number are divisible by 4, the number itself is divisible by 4.If a number ends in 0 or 5, it is divisible by 5.If a number is divisible by both 2 and 3, it is divisible by 6.If you double the last digit and subtract it from the rest of the number and the answer is 0 or divisible by 7, it is divisible by 7. For example, 4364: 4 doubled is 8. 436 - 8 = 424. You still cannot readily tell if the number is divisible by 7, so you can do it again: 4 doubled is 8. 42 - 8 = 34. 34 is not divisible by 7 so 436 is not divisible by 7If the last three digits of a number are divisible by 8, the number itself is divisible by 8.If the sum of the digits of a number is divisible by 9, the number itself is divisible by 9.If a number ends with 0, it is divisible by 10.If you add every other digit and then subtract the rest of the digits and the answer is 0 or is divisible by 11, the number itself is divisible by 11. For example: 1364: 1+ 6 = 7 and 7 - 3 - 4 = 0. The number is divisible by 11.If the number is divisible by 3 and 4, it is divisible by 12.There are more divisibility rules that can be used for large numbers.

One and itself.

I'm not quite sure about that theory, but if all the numbers in the number add up to a number that's dividable by 3, then the number itself would then be divisible by 3. Ex. 141 1+4+1= 6 6 is divisible by 3, so 141 is too. 141/3= 47.

Yes. Every number is divisible by itself or 1.

Every three-digit number that ends with a zero or a 5 is divisible by 5.It doesn't matter what the first 2 digits are.

1795 is a composite number because it is divisible by 5. Every number (except 5) ending with digit 5 or 0 is divisible by 5.

135. Every increase of 30 is also. Such as 165, 195, 225.