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Is 78 divisible by 6 and 9?
Using the tests for divisibility:Divisible by 3:Add the digits and if the sum is divisible by 3, so is the original number: 6 + 8 + 4 = 18 which is divisible by 3, so 684 is divisible by 3Divisible by 6:Number is divisible by 2 and 3: Divisible by 2:If the number is even (last digit divisible by 2), then the whole number is divisible by 2. 684 is even so 684 is divisible by 2.Divisible by 3:Already shown above to be divisible by 3. 684 is divisible by both 2 & 3 so 684 is divisible by 6Divisible by 9:Add the digits and if the sum is divisible by 9, so is the original number: 6 + 8 + 4 = 18 which is divisible by 9, so 684 is divisible by 9Thus 684 is divisible by all 3, 6 & 9.
Is there a number divisible by 6. But not 3?
yeah3 9 15 21 27 and so on(every other multiple of three)But if you have a large number, like 755253, and don't have a calculator handy, then use sum of digits to determine if divisible by 3.Then if the number is divisible by 3 and divisible by 2, then it is also divisible by 6.So in this case: 7 + 5 + 5 + 2 + 5 + 3 = 27, which is divisible by 3, but the original number is odd, so the number is not divisible by 6.
How can you tell if a number is divisible by 12?
If a number is divisible by both three and four, it's divisible by twelve.
Is 423 divisible by 6?
A number is divisible by 6 if it is divisible both by 2 and 3 1240 is even then is divisible by 2 1+2+4+0 = 7 which is not divisible by 3 then 1240 is not divisible by 3 Thus 1240 is not divisible by 6
What are the prime factorizations for the number 78?
2 x 3 x 13 = 78 2 x 3 x 13
Is 78 divisible by every number?
78 is evenly divisible by 1, 2, 3, and 13.
How can you know if 6 is a factor of 78?
For a number to be divisible by 6, it has to be divisible by 2 and 3, because 2*3=6.In other words, we could divide the number we're factorising (78) by the prime factors of the number we're testing (6, which is 2*3). We start by dividing by 2, because we know 78 is even: 78/2=39. Then, we divide the new number by the other prime factor - 3. 39/3=13 13 is a whole number with no remainders, therefore we can say that 78 is divisible by 6, and therefore 6 is a factor of 78. (6*13=78)
What number is divisible by 3 2 and 13?
All of the multiples of 78 are. There are an infinite number of them.
Is 2360 divisible by 30?
No, because 2360/30 is 78 and 2/3, which is not a whole number.
What are divisible by 78?
All multiples of 78 are divisible by it. For example ( 78 X 2, 156) or (78 x 3 , 234) etc.
Is 78 divisible by 2 3 or both?
Both.
What number is divisible by 2 and 3 but not 9?
They are divisible by : 6, 12, 24, 30, 42, 48, 60, 66, 78, 84, and 96.
What is 78 divisible by?
2, 3, 6, and 39
Is 5232 divisible by 6?
Since 5232 is divisible by both 2 and 3, it is divisible by 6.A number must be divisible by both 2 and 3 to be divisible by 6.The number 5232 is even, so it is divisible by 2.If you add the individual digits in the number (5+2+3+2=12) you get a number that is divisible by 3, meaning the original number (5232) is also divisible by 3.
If the number is divisible by 2 and 3 the whole number is divisible by?
It is divisible by 6
If a number is divisble by both 2 and 3 is it divisible by 6?
Any number that is divisible by both 2 and 3 is divisible by 6.
Is 234 divisible by 3 6 and 9?
Using the tests for divisibility:Divisible by 3:Add the digits and if the sum is divisible by 3, so is the original number: 2 + 3 + 4 = 9 which is divisible by 3, so 234 is divisible by 3Divisible by 6:Number is divisible by 2 and 3: Divisible by 2:If the number is even (last digit divisible by 2), then the whole number is divisible by 2. 234 is even so 234 is divisible by 2.Divisible by 3:Already shown above to be divisible by 3. 234 is divisible by both 2 & 3 so 234 is divisible by 6Divisible by 9:Add the digits and if the sum is divisible by 9, so is the original number: 2 + 3 + 4 = 9 which is divisible by 9, so 234 is divisible by 9Thus 234 is divisible by all 3, 6 & 9.
