Using the tests for divisibility:Divisible by 3:Add the digits and if the sum is divisible by 3, so is the original number: 6 + 8 + 4 = 18 which is divisible by 3, so 684 is divisible by 3Divisible by 6:Number is divisible by 2 and 3: Divisible by 2:If the number is even (last digit divisible by 2), then the whole number is divisible by 2. 684 is even so 684 is divisible by 2.Divisible by 3:Already shown above to be divisible by 3. 684 is divisible by both 2 & 3 so 684 is divisible by 6Divisible by 9:Add the digits and if the sum is divisible by 9, so is the original number: 6 + 8 + 4 = 18 which is divisible by 9, so 684 is divisible by 9Thus 684 is divisible by all 3, 6 & 9.
yeah3 9 15 21 27 and so on(every other multiple of three)But if you have a large number, like 755253, and don't have a calculator handy, then use sum of digits to determine if divisible by 3.Then if the number is divisible by 3 and divisible by 2, then it is also divisible by 6.So in this case: 7 + 5 + 5 + 2 + 5 + 3 = 27, which is divisible by 3, but the original number is odd, so the number is not divisible by 6.
If a number is divisible by both three and four, it's divisible by twelve.
A number is divisible by 6 if it is divisible both by 2 and 3 1240 is even then is divisible by 2 1+2+4+0 = 7 which is not divisible by 3 then 1240 is not divisible by 3 Thus 1240 is not divisible by 6
2 x 3 x 13 = 78 2 x 3 x 13
78 is evenly divisible by 1, 2, 3, and 13.
For a number to be divisible by 6, it has to be divisible by 2 and 3, because 2*3=6.In other words, we could divide the number we're factorising (78) by the prime factors of the number we're testing (6, which is 2*3). We start by dividing by 2, because we know 78 is even: 78/2=39. Then, we divide the new number by the other prime factor - 3. 39/3=13 13 is a whole number with no remainders, therefore we can say that 78 is divisible by 6, and therefore 6 is a factor of 78. (6*13=78)
All of the multiples of 78 are. There are an infinite number of them.
The prime factors of 78 are 2, 3, and 13. To find the prime factors of a number, you can start by dividing the number by the smallest prime number, which is 2. If the number is divisible by 2, continue dividing by 2 until you reach a point where it is no longer divisible by 2. Then, move on to the next prime number, which is 3. Repeat the process until you have factored the number completely into its prime factors.
No, because 2360/30 is 78 and 2/3, which is not a whole number.
All multiples of 78 are divisible by it. For example ( 78 X 2, 156) or (78 x 3 , 234) etc.
Both.
They are divisible by : 6, 12, 24, 30, 42, 48, 60, 66, 78, 84, and 96.
2, 3, 6, and 39
Since 5232 is divisible by both 2 and 3, it is divisible by 6.A number must be divisible by both 2 and 3 to be divisible by 6.The number 5232 is even, so it is divisible by 2.If you add the individual digits in the number (5+2+3+2=12) you get a number that is divisible by 3, meaning the original number (5232) is also divisible by 3.
It is divisible by 6
Any number that is divisible by both 2 and 3 is divisible by 6.