3 and 9. 93 has a digit sum of 12, initially, which is divisible by 3, but not by 9. So 93 is divisible by 3, but not by 9. 99 has a digit sum of 18, initially, which is divisible by 3 and 9. So 99 is divisible by both 3 and 9.
Except for zero, any number can divide into any other number. If the answer is a whole number, the larger number is said to be divisible by the smaller. 9 divided by 4 = 2.25 9 is not divisible by 4. 9 divided by 3 = 3 9 is divisible by 3.
Yes. If the sum of a number's digits add up to 3 (or a multiple of 3) then the number is divisible by 3. 5 + 3 + 1 = 9 : as 9 is a multiple of 3 then 531 is divisible by 3 (177 x 3 = 531). NOTE : A similar process applies to identify if a number is divisible by 9. If the sum of the number's digits add up to 9 (or a multiple of 9) then the number is divisible by 9. 5 + 3 + 1 = 9 : 531 = 59 x 9.
NO. 1110 is not divisible by 9. A number is divisible by 9 if the sum of its digits is divisible by 9. 1110 = 1 + 1 + 1 + 0 = 3 (3 is not divisible by 9, thus, 1110 is not divisible by 9.)
Numbers divisible by nine are infinite. They start with these: 9, 18, 27, 36, 45, 54, 63 . . .
No, 9 is divisible by 3 and 9, but not six 3 x 9 = 27, also not divisible by 6
Every number is divisible by any non-zero number. Furthermore, 4770 is evenly divisible by both 3 and 9.
Every number is divisible by 9 but the answer wont necessarily be a whole number.
Every number is divisible by any non-zero number. Furthermore, 405 is evenly divisible by both 3 and 9.
If a number is not divisible by 3 then it is not divisible by 9.
Yes, any number divisible by 9 is also divisible by 3.
To check for divisibility by 9 sum the digits of the number and if this sum is divisible by 9 then so is the original number. For 32643: 3 + 2 + 6 + 4 + 3 = 18 which is divisible by 9 so 32643 is divisible by 9. As 9 = 3 × 3, any number divisible by 9 is also divisible by 3, thus as 32643 is divisible by 9 it is also divisible by 3. However, for completeness: to check for divisibility by 3 sum the digits of the number and if this sum is divisible by 3 then so is the original number. For 32643: 3 + 2 + 6 + 4 + 3 = 18 which is divisible by 3 so 32643 is divisible by 3.
There are many numbers between 500 and 1000 divisible by 3 and 9. Any number divisible by 9 is divisible by 3. How about 900?
Yes, since 10 is divisible by 5. Likewise, every number which is divisible by 9 is also divisible by 3.
235910 is not divisible by 2685. 235910 divided by 2685 is 87.86219739292365 Out of that list, 2685 is divisible by 3 and 5.
999 is divisible by 9, but not by six; the next lower number divisible by 9 is 990, which is also divisible by 6, so that's the answer. Some shortcuts for divisibility: 0 is divisible by any number. If the last digit of a number is divisible by 2, the number itself is divisible by 2. If the sum of the digits of a number is divisible by 3, the number itself is divisible by 3. If the last TWO digits of a number are divisible by 4, the number itself is divisible by 4. If the last digit of a number is divisible by 5, the number itself is divisible by 5. If a number is divisible by both 2 and 3, it is divisible by 6. If the last THREE digits of a number are divisible by 8, the number itself is divisible by 8. If the sum of the digits of a number is divisible by 9, the number itself is divisible by 9. 990: 9+9+0=18, which is divisible by 9, so 990 is divisible by 9. 18 is also divisible by 3, so 990 is divisible by 3, and since 990 ends in 0 it's also divisible by 2, meaning that it's divisible by 6 as well.
It is impossible since 3 can already go into 9.